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For the following exercises, use the Mean Value Theorem and find all points 0 < c < 2 such that ƒ(2) — ƒ(0) = f'(c)(2 – 0). 14. f(x) = x³ Solution C = 2√3 15. f(x) = sin(TX) 16. f(x) = cos(2x)

For the following exercises, use the Mean Value Theorem and find all points 0 < c < 2 such that ƒ(2) — ƒ(0) = f'(c)(2 – 0). 14. f(x) = x³ Solution C = 2√3 15. f(x) = sin(TX) 16. f(x) = cos(2x)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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please i need help with 16 only

For the following exercises, use the Mean Value Theorem and find all points 0 < c < 2 such that ƒ(2) — ƒ(0) = f'(c)(2 — 0). 14. f(x) = x³ Solution C = 2√3 15. f(x) = sin(x) 16. f(x) = cos(2πx)
Transcribed Image Text:For the following exercises, use the Mean Value Theorem and find all points 0 < c < 2 such that ƒ(2) — ƒ(0) = f'(c)(2 — 0). 14. f(x) = x³ Solution C = 2√3 15. f(x) = sin(x) 16. f(x) = cos(2πx)
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please i dont understand that you did after step 3 from 0=sin(2pi c)

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