For the following exercise, determine the point(s), if any, at which each function is discontinuous. Classify any discontinuity as jump, removable, infinite, or other. X ƒ(x) = ²x² = x 2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
### Section 2.4

**Exercise 7**

For the following exercise, determine the point(s), if any, at which each function is discontinuous. Classify any discontinuity as jump, removable, infinite, or other.

\[ f(x) = \frac{x}{x^2 - x} \]

---

#### Detailed Analysis:

To identify the points of discontinuity in the given function \( f(x) = \frac{x}{x^2 - x} \), follow these steps:

1. **Factor the denominator**:
   \[
   x^2 - x = x(x - 1)
   \]
2. **Identify the points where the denominator is zero**:
   \[
   x(x - 1) = 0
   \]
   \[
   x = 0 \quad \text{or} \quad x = 1
   \]

At \( x = 0 \) and \( x = 1 \), the denominator becomes zero, making the function undefined at these points. These are potential points of discontinuity.

3. **Classify the discontinuities**:
   - **At \( x = 0 \)**: The function has an infinite discontinuity because as \( x \) approaches 0, the function tends to infinity or negative infinity. 
   - **At \( x = 1 \)**: The function also has an infinite discontinuity because as \( x \) approaches 1, the function again tends to infinity or negative infinity.

By examining the function \( f(x) = \frac{x}{x(x - 1)} \), it's clear that the function is undefined at \( x = 0 \) and \( x = 1 \) due to division by zero, both leading to infinite discontinuities.
Transcribed Image Text:### Section 2.4 **Exercise 7** For the following exercise, determine the point(s), if any, at which each function is discontinuous. Classify any discontinuity as jump, removable, infinite, or other. \[ f(x) = \frac{x}{x^2 - x} \] --- #### Detailed Analysis: To identify the points of discontinuity in the given function \( f(x) = \frac{x}{x^2 - x} \), follow these steps: 1. **Factor the denominator**: \[ x^2 - x = x(x - 1) \] 2. **Identify the points where the denominator is zero**: \[ x(x - 1) = 0 \] \[ x = 0 \quad \text{or} \quad x = 1 \] At \( x = 0 \) and \( x = 1 \), the denominator becomes zero, making the function undefined at these points. These are potential points of discontinuity. 3. **Classify the discontinuities**: - **At \( x = 0 \)**: The function has an infinite discontinuity because as \( x \) approaches 0, the function tends to infinity or negative infinity. - **At \( x = 1 \)**: The function also has an infinite discontinuity because as \( x \) approaches 1, the function again tends to infinity or negative infinity. By examining the function \( f(x) = \frac{x}{x(x - 1)} \), it's clear that the function is undefined at \( x = 0 \) and \( x = 1 \) due to division by zero, both leading to infinite discontinuities.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,