For the emitter-bias network, determine: a. Ig b. lc C.VCE d. Vc e. VE f. VB g. VBC Vi 430 ΚΩ 10 μF H +20 V • 2 ΚΩ 10 μF HH 1kQ2 H 40 μF

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Q: la) VE (6) Ic (C) VC

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Q: A BJT has an Ig of 50 μA and a Bpc of 75; lc is: O 375 mA O 3.75 mA O 37.5 mA O 0.375 mA

A: Second option is correct. The detailed solution is provided below.

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Q: The BJT shown has β = 80. What is the value of VI that makes VEC equal 1.5 V? a.   VI = 2.044 V…

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Q: BJT with VCC=10v, RC=9.8Kohm, B=100 and RB=200Kohm. VBB= ? *

A: VCC=10 VRC=9.8 kΩβ=100RB=200 kΩVBB=? emitter current IE=VCC-VBERBβ+RC=10-0.7200kΩ100+9.8kΩIE=0.7 mA

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Norton Theorem

In the current circuit law, the Norton theorem (also known as the Mayer-Norton theorem) is a simplification that can be applied to networks generated by a constant line of opposition, power sources, and current assets. In two network terminals, it can be switched on with a current supply and single resistor respectively.