For the diprotic weak acid H₂A, Kal = 2.8 × 10-6 and K₁2 = 7.5 × 10-⁹. What is the pH of a 0.0800 M solution of H₂A? pH = 3.32 What are the equilibrium concentrations of H₂A and A²- in this solution?
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![For the diprotic weak acid H₂A, Kal
What is the pH of a 0.0800 M solution of H₂ A?
pH = = 3.32
[H₂A] = 0.0795
[A²-] =
What are the equilibrium concentrations of H₂A and A²- in this solution?
0.00047
=
2.8 x 10-6 and K₂2
Incorrect
= 7.5 × 10-⁹.
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