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For the differential equation dy dx 5 + ex+y = 0, find its general solution.

For the differential equation dy dx 5 + ex+y = 0, find its general solution.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
For the differential equation dy 1. y = ln 2. y = ln (i) find its general solution. ex In (en + C) 6 = In (#7) + C 3. y In - In (es + C) 5 4. y In 5 5 = In (₁) ex + C 6 5. y = ln = m ( x + c) + C 1. yo(x) dx 2. yo(x) 3. yo(x) = + (ii) Then find the particular solution yo such that y(0) = 0. = In (5e² + 4) = In ( ² + 4) ex 5 ex+y In (5+₁) ex +4 4. yo(x) In - m (56) ex 5. yo(x) = ln( (5) 1. yo(ln 2) = ln( In(-/-) (iii) For the particular solution yo in (ii), deter- mine the value of yo(ln 2). = 0, 2. yo (In 2) In 3. yo(ln 2) = ln (1)
Transcribed Image Text:For the differential equation dy 1. y = ln 2. y = ln (i) find its general solution. ex In (en + C) 6 = In (#7) + C 3. y In - In (es + C) 5 4. y In 5 5 = In (₁) ex + C 6 5. y = ln = m ( x + c) + C 1. yo(x) dx 2. yo(x) 3. yo(x) = + (ii) Then find the particular solution yo such that y(0) = 0. = In (5e² + 4) = In ( ² + 4) ex 5 ex+y In (5+₁) ex +4 4. yo(x) In - m (56) ex 5. yo(x) = ln( (5) 1. yo(ln 2) = ln( In(-/-) (iii) For the particular solution yo in (ii), deter- mine the value of yo(ln 2). = 0, 2. yo (In 2) In 3. yo(ln 2) = ln (1)
In (-/-) 4. yo(ln 2) = In n(²7) 5. yo(ln 2) In
Transcribed Image Text:In (-/-) 4. yo(ln 2) = In n(²7) 5. yo(ln 2) In
Expert Solution
Step 1

The given differential equation is 5dydx+ex+y=0

We have to find the general solution of the differential equation.

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