For the delivery truck shown:The mass of the truck is 4000 kg.The horizontal distance from the rear tires tothe center of mass, G, is L1 = 3 mThe vertical distance from the ground to G isd = 3mThe horizontal distance from the rear tires tothe front tires is L2 = 5 m.dThe delivery truck is traveling at 20 m/swhen the brakes are applied.The truck skids to a stop, so that the frictionforce is applied to the tires by the road.*The coefficient dynamic friction is uk = 0.60*If it did not skid, then the friction forcewould be between the brake pads and thebrake disc, which would be above the road.Calculate the distance that the truck travels before it stops.Use Σ MA = Ia + d x m*a for the following:'O'Calculate the left side of this equation: Σ MAGL1 →L2Calculate the right side of this equation: I*α + d x m*ad+ x m*a is from r x m*a (cross product), so, determine the sign by considering the cross product.Set the left and right right sides equal to each other and solve for NBCalculate the normal force on each of the rear tires and each of the front tires.

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For the delivery truck shown: The mass of the truck is 4000 kg. The horizontal distance from the rear tires to the center of mass, G, is L1 = 3 m The vertical distance from the ground to G is d=3m The horizontal distance from the rear tires to the front tires is L2 = 5 m.

For the delivery truck shown: The mass of the truck is 4000 kg. The horizontal distance from the rear tires to the center of mass, G, is L1 = 3 m The vertical distance from the ground to G is d=3m The horizontal distance from the rear tires to the front tires is L2 = 5 m.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Forming and Shaping

Metal forming is a category of metalworking process through which the material can be given the desired shape and size by subjecting it to plastic deformation, where the component undergoes bulk deformation process upon application of loads. Unlike the shearing and machining process, the material does not undergo up to a failure point as indicated in the stress-strain curve. Hence, the stresses induced during the forming process are greater than yield strength but less than the failure strength of the material. The process does not lead to the loss of material, so it can be said to be an economical process. During forming, the material is subjected to tensile forces, compressive forces, bending, and shearing loading conditions. The material should possess the property of ductility to undergo the forming process.

Question

For the delivery truck shown:
The mass of the truck is 4000 kg.
The horizontal distance from the rear tires to
the center of mass, G, is L1 = 3 m
The vertical distance from the ground to G is
d = 3m
The horizontal distance from the rear tires to
the front tires is L2 = 5 m.
d
The delivery truck is traveling at 20 m/s
when the brakes are applied.
The truck skids to a stop, so that the friction
force is applied to the tires by the road.*
The coefficient dynamic friction is uk = 0.60
*If it did not skid, then the friction force
would be between the brake pads and the
brake disc, which would be above the road.
Calculate the distance that the truck travels before it stops.
Use Σ MA = Ia + d x m*a for the following:
'O'
Calculate the left side of this equation: Σ MA
G
L1 →
L2
Calculate the right side of this equation: I*α + d x m*a
d+ x m*a is from r x m*a (cross product), so, determine the sign by considering the cross product.
Set the left and right right sides equal to each other and solve for NB
Calculate the normal force on each of the rear tires and each of the front tires.

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