For the continuous-time periodic signal: æ(t) = 2 + cos(t) + 4sin(t), determine the fundamental frequency and the Fourier coefficients a such that x(t) = akej kwot O a. wo = 3,90 = ₁a2= a_2=2, a5 = a*5 = 2j O b. wo = 7,90 = 2a2a-2=2, a5 = a*5 = -2j ,ao = 2, a₂ = a_2 = 1, a5=a²5= -2j O.. c. wo = O d. wo 3,90 = 2, a₂ = a_2= 1⁄2, a5 = a*5=2j
For the continuous-time periodic signal: æ(t) = 2 + cos(t) + 4sin(t), determine the fundamental frequency and the Fourier coefficients a such that x(t) = akej kwot O a. wo = 3,90 = ₁a2= a_2=2, a5 = a*5 = 2j O b. wo = 7,90 = 2a2a-2=2, a5 = a*5 = -2j ,ao = 2, a₂ = a_2 = 1, a5=a²5= -2j O.. c. wo = O d. wo 3,90 = 2, a₂ = a_2= 1⁄2, a5 = a*5=2j
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Fourier Analysis of Discrete and Continuous Time Signals and Systems

Transcribed Image Text:For the continuous-time periodic signal: æ(t) = 2 + cos(t) + 4sin(t), determine the fundamental frequency and the Fourier coefficients a
such that
x(t) = akej kwot
O a. wo = 3,90 = 1/₁a2= a_2 = 2, a5 = a*5 = 2j
품, ao = a2 = a_2=2, a5 = a*5 = -2j
wo =
ao = 2, a₂ = a_2 = 1, a5=a²5= -2j
O d. wo 3,90 = 2₁ a₂ = a_2 = √2, a5 = a*5=2j
O b. wo =
O. c.
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