For the combustion temperature, Keq huge number!!!) Given the initial conditions below, which of the following quantities will be essentially zero? of ethanol at room = 6.7 x 10227. (That's a really Reaction C₂H5OH + Initial Change Final 2 3 0₂ 2 = 2 CO₂ 0 + 3 H₂O 0

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Chapter1: Chemical Foundations
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For the combustion of ethanol at room
temperature, Keq = 6.7 x 10227. (That's a really
huge number!!!) Given the initial conditions
below, which of the following quantities will be
essentially zero?
Reaction C₂H5OH +
Initial
Change
Final
2
3
0₂
2
11
2
CO₂
0
+
3
H₂O
0
Transcribed Image Text:For the combustion of ethanol at room temperature, Keq = 6.7 x 10227. (That's a really huge number!!!) Given the initial conditions below, which of the following quantities will be essentially zero? Reaction C₂H5OH + Initial Change Final 2 3 0₂ 2 11 2 CO₂ 0 + 3 H₂O 0
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