Please answer correctly. Thank you For the circuit shown, the node voltages with respect to the reference nodeare given:Va=4.83Z56.5° VV = 8.69Z102.3° VVe = 3.90/114.8° VVa = 1.98474.1° VWhat is the value of the current Ip?VaVaj3 012- 45° AIA404 0-j1NVpVcIDIB↑ )-j5NIcj2 n4415° A J3.01z-45° A40j1040VpIpVeIBj2 01 )4415° A-j5 0O 3.61/28.9° AO 3.612- 151.1° AO 4.96/2.5° A4.96/ 177.5° A

For the circult shown, the node voltages with respect to the reference node are given: Va = 4.83456.5° V V = 8.69Z102.3° V V. = 3.90/114.8° V Va = 1.98274.1° V What is the value of the current Ip? Va Va j3 N 12-45° A IA 40 40 -j1N Vp Vc ID IB ↑ ) -j50 Ic j2 N 4415° A

For the circult shown, the node voltages with respect to the reference node are given: Va = 4.83456.5° V V = 8.69Z102.3° V V. = 3.90/114.8° V Va = 1.98274.1° V What is the value of the current Ip? Va Va j3 N 12-45° A IA 40 40 -j1N Vp Vc ID IB ↑ ) -j50 Ic j2 N 4415° A

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Please answer correctly. Thank you

For the circuit shown, the node voltages with respect to the reference node
are given:
Va
=4.83Z56.5° V
V = 8.69Z102.3° V
Ve = 3.90/114.8° V
Va = 1.98474.1° V
What is the value of the current Ip?
Va
Va
j3 0
12- 45° A
IA
40
4 0
-j1N
Vp
Vc
ID
IB
↑ )
-j5N
Ic
j2 n
4415° A

J3.0
1z-45° A
40
j10
40
Vp
Ip
Ve
IB
j2 0
1 )4415° A
-j5 0
O 3.61/28.9° A
O 3.612- 151.1° A
O 4.96/2.5° A
4.96/ 177.5° A

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