For the circular arch, find the internal axial force at a location 97 ft to the right of point A. Use the correct positive internal force sign convention. If it helps you, the radius of the arch is 75 ft.
For the circular arch, find the internal axial force at a location 97 ft to the right of point A. Use the correct positive internal force sign convention. If it helps you, the radius of the arch is 75 ft.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:### Circular Arch Analysis
**Problem Statement:**
For the circular arch, determine the internal axial force at a point 97 feet to the right of point A. Use the correct positive internal force sign convention as per engineering standards. The radius of the arch is 75 feet.
**Diagram Explanation:**
The diagram shows a symmetrical circular arch with specific dimensions and forces:
- **Supports:**
- The left end of the arch is labeled as Point A.
- The right end of the arch is labeled as Point B.
- **Forces Applied:**
- A downward force of 60 kips (k) is applied 20 feet from Point A.
- A downward force of 40 kips (k) is applied at the top of the arch, 60 feet from both A and B.
- A downward force of 50 kips (k) is applied 20 feet from Point B.
- **Hinge:**
- A hinge is located at the top of the arch, equidistant from points A and B.
- **Dimensions:**
- The total span of the arch from Point A to Point B is 120 feet.
- The arch is divided into segments of 20 ft, 20 ft, 20 ft, 40 ft, and 20 ft respectively.
- The vertical clearance at the highest point is 30 feet.
**Objective:**
To find the internal axial force at a specific location 97 feet to the right of point A, using diagram elements and given measurements.
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