For the circuit shown, what is the Thevenin equivalent impedance, ZT, in polar form? j30 12 0 2452.6° A -j5 0 14430° V O 13.0/22.6°N O 12.1729.5°N O 13.02 – 22.6° N O 12.17/ = 9.5° N
For the circuit shown, what is the Thevenin equivalent impedance, ZT, in polar form? j30 12 0 2452.6° A -j5 0 14430° V O 13.0/22.6°N O 12.1729.5°N O 13.02 – 22.6° N O 12.17/ = 9.5° N
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Transcribed Image Text:**For the circuit shown, what is the Thevenin equivalent impedance, \( Z_T \), in polar form?**
**Circuit Description:**
1. **Components:**
- A current source of \( 2 \angle 52.6^\circ \) A.
- A resistor with a resistance of \( 12 \, \Omega \).
- An inductor with an inductive reactance of \( j3 \, \Omega \).
- A capacitor with a capacitive reactance of \( -j5 \, \Omega \).
- A voltage source of \( 14 \angle 30^\circ \) V.
2. **Configuration:**
- The current source is connected in series with the resistor.
- The inductor and capacitor are connected in parallel.
- The voltage source is connected at the right side of the circuit.
**Options for Thevenin Equivalent Impedance \( Z_T \):**
- \( 13.0 \angle 22.6^\circ \, \Omega \)
- \( 12.17 \angle 9.5^\circ \, \Omega \)
- \( 13.0 \angle -22.6^\circ \, \Omega \)
- \( 12.17 \angle -9.5^\circ \, \Omega \)
For educational purposes, students should analyze the circuit using techniques such as converting to phasor form and applying the Thevenin theorem to determine the equivalent impedance.
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