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For the circuit shown in the figure below, use Kirchhoff's rules to obtain equations for the upper loop, the lower loop, and the node on the left side. In each case suppress units for clarity and simplify, combining like terms. (Use the following as necessary: I18, I12, and I36.) 18.0 V 18 5.00 N 8.00 0 12.0 V 11.0 N 7.00 N + 12 + 5.00 N 36.0 V (a) the upper loop = 30 (b) the lower loop = 24 (c) the node on the left side = I18 (d) Solve the node equation for I36: = 136 (e) Using the equation found in (d), eliminate I36 from the equation found in part (b). = 24 (f) Solve the equations found in part (a) and part (e) simultaneously for the two unknowns for I,, and I,3, respectively. 112 = I18 =| A A (g) Substitute the answers found in part (f) into the node equation found in part (d), solving for I35: I36 = A

For the circuit shown in the figure below, use Kirchhoff's rules to obtain equations for the upper loop, the lower loop, and the node on the left side. In each case suppress units for clarity and simplify, combining like terms. (Use the following as necessary: I18, I12, and I36.) 18.0 V 18 5.00 N 8.00 0 12.0 V 11.0 N 7.00 N + 12 + 5.00 N 36.0 V (a) the upper loop = 30 (b) the lower loop = 24 (c) the node on the left side = I18 (d) Solve the node equation for I36: = 136 (e) Using the equation found in (d), eliminate I36 from the equation found in part (b). = 24 (f) Solve the equations found in part (a) and part (e) simultaneously for the two unknowns for I,, and I,3, respectively. 112 = I18 =| A A (g) Substitute the answers found in part (f) into the node equation found in part (d), solving for I35: I36 = A

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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please help with parts E, F, G. Thank you! :) 

For the circuit shown in the figure below, use Kirchhoff's rules to obtain equations for the upper loop, the lower loop, and the node on the left side. In each case suppress units for clarity and simplify, combining like terms. (Use the following as necessary: I18, I12, and I36.) 18.0 V 5.00 N + 8.00 N 12.0 V 11.0 N 7.00 N + 12 5.00 N I36 36.0 V (a) the upper loop = 30 (b) the lower loop = 24 (c) the node on the left side = I 18 (d) Solve the node equation for I36: = I 36 (e) Using the equation found in (d), eliminate I36 from the equation found in part (b). = 24 (f) Solve the equations found in part (a) and part (e) simultaneously for the two unknowns for I,, and I,8, respectively. 12 I12 = I 18 = A A (g) Substitute the answers found in part (f) into the node equation found in part (d), solving for I36: 136 A = +
Transcribed Image Text:For the circuit shown in the figure below, use Kirchhoff's rules to obtain equations for the upper loop, the lower loop, and the node on the left side. In each case suppress units for clarity and simplify, combining like terms. (Use the following as necessary: I18, I12, and I36.) 18.0 V 5.00 N + 8.00 N 12.0 V 11.0 N 7.00 N + 12 5.00 N I36 36.0 V (a) the upper loop = 30 (b) the lower loop = 24 (c) the node on the left side = I 18 (d) Solve the node equation for I36: = I 36 (e) Using the equation found in (d), eliminate I36 from the equation found in part (b). = 24 (f) Solve the equations found in part (a) and part (e) simultaneously for the two unknowns for I,, and I,8, respectively. 12 I12 = I 18 = A A (g) Substitute the answers found in part (f) into the node equation found in part (d), solving for I36: 136 A = +
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