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For the circuit shown, if Is = 3Z-80° A and Z = 3Z2, what is the value of I,? %3D | Is (1 Z2 O I2 = 2.25Z – 40° A O I2 = 0.75/ – 40° A O I2 = 0.75/- 80° A O 2 = 2.25/- 80° A

For the circuit shown, if Is = 3Z-80° A and Z = 3Z2, what is the value of I,? %3D | Is (1 Z2 O I2 = 2.25Z – 40° A O I2 = 0.75/ – 40° A O I2 = 0.75/- 80° A O 2 = 2.25/- 80° A

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Problem Statement:** For the circuit shown, if \( I_S = 3 \angle -80^\circ \, \text{A} \) and \( Z_1 = 3Z_2 \), what is the value of \( I_2 \)? **Diagram Explanation:** The circuit diagram shows a current source labeled \( I_S \), which provides a current flowing upward. There are two currents labeled \( I_1 \) and \( I_2 \) flowing downward through two impedances \( Z_1 \) and \( Z_2 \) respectively. The impedances are connected in parallel to the current source. **Answer Options:** - \( I_2 = 2.25 \angle -40^\circ \, \text{A} \) - \( I_2 = 0.75 \angle -40^\circ \, \text{A} \) - \( I_2 = 0.75 \angle -80^\circ \, \text{A} \) - \( I_2 = 2.25 \angle -80^\circ \, \text{A} \)
Transcribed Image Text:**Problem Statement:** For the circuit shown, if \( I_S = 3 \angle -80^\circ \, \text{A} \) and \( Z_1 = 3Z_2 \), what is the value of \( I_2 \)? **Diagram Explanation:** The circuit diagram shows a current source labeled \( I_S \), which provides a current flowing upward. There are two currents labeled \( I_1 \) and \( I_2 \) flowing downward through two impedances \( Z_1 \) and \( Z_2 \) respectively. The impedances are connected in parallel to the current source. **Answer Options:** - \( I_2 = 2.25 \angle -40^\circ \, \text{A} \) - \( I_2 = 0.75 \angle -40^\circ \, \text{A} \) - \( I_2 = 0.75 \angle -80^\circ \, \text{A} \) - \( I_2 = 2.25 \angle -80^\circ \, \text{A} \)
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