Answered: For the circuit of shown figure, the…

For the circuit of shown figure, the nodal equation for node (3) in s-domain is: vi 0.25F 6H 3H ell V2 V3 0.5F -3t 5e ut) ( T 6Ω 3e sin(3t)u(t)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

100%

Od.
V + 3s²V2 – (3s² + 1)V3
36s
-
(s2 + 10s + 25)
12s
O e.
2V1 – (s + 2)V2 + sV3
(s2 + 4s + 4)
f.
60s
(3s2 + 6)V1 – (3s² + 4)V2 – 2V3
(s + 3)
(3s² + 5)V, – 3V2 + 35²V3 = 0
O h.
60s
(3s2 + 6)V1 + (3s² + 4)V2 – 2V3
(s + 3)
i.
(-3s² – 4)V1 + (9s² + 2s + 4)V2 – 6S²V3 = 0

For the circuit of shown figure, the nodal equation for node (3) in s-domain is:
Vi
0.25F
6H
3H
V2
ll
V3
0.5F
-3t
se ut)
Son
( )se'sin(3t)u(t)
6Ω
(3s² + 5)V1 – 3V2 – 35²V3 = 0
а.
O b.
-8s
2sV, + V2 – (2s + 1)V3
%3D
(s² + 16)
C.
36s
Vị + 3s2V2 – (3s² +1)V3
(s2 + 8s + 25)
ell

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