1. For the circuit of Figure 1, a load having an impedance of 28+j16Q is fed from a voltagesource through a line having an impedance of 2+J42. The effective or rms value of thesource voltage is 220V.(a) Calculate the load current IL and voltage VL(b) Calculate the average and reactive power delivered to the load.(c) Calculate the average and reactive power delivered to the line.(d) Calculate the average and reactive power supplied by the source.20j422803220/0V (rms)j16nSource-Line--LoadFigure 1

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Engineering

Electrical Engineering

For the circuit of Figure 1, a load having an impedance of 28+j162

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Current Division Method

The generalized current divider formula is given by the following relation below,

Question

1. For the circuit of Figure 1, a load having an impedance of 28+j16Q is fed from a voltage
source through a line having an impedance of 2+J42. The effective or rms value of the
source voltage is 220V.
(a) Calculate the load current IL and voltage VL
(b) Calculate the average and reactive power delivered to the load.
(c) Calculate the average and reactive power delivered to the line.
(d) Calculate the average and reactive power supplied by the source.
20
j42
2803
220/0
V (rms)
j16n
Source
-Line-
-Load
Figure 1

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