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For the circuit given below: R1 is 47K, R2 is 39K, R3 is 68K and R4 is 56K, B1 is 1.5 V, B2 is 3.0 V and the current source is equal to the last digit of your student ID Here R is the last digit of your roll no 47 kN 39 kn 1.5 V R Amphere 3.0 V 68 k? 56 kN

For the circuit given below: R1 is 47K, R2 is 39K, R3 is 68K and R4 is 56K, B1 is 1.5 V, B2 is 3.0 V and the current source is equal to the last digit of your student ID Here R is the last digit of your roll no 47 kN 39 kn 1.5 V R Amphere 3.0 V 68 k? 56 kN

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Solve the circuit from the images using Mesh analysis

R = 4

For the circuit given below: R1 is 47K, R2 is 39K, R3 is 68K and R4 is 56K, B1 is 1.5 V, B2 is 3.0 V and the current source is equal to the last digit of your student ID Here R is the last digit of your roll no 47 kN 39 kN R Amphere 3.0 V 1.5 V 68 kN 56 kN
Transcribed Image Text:For the circuit given below: R1 is 47K, R2 is 39K, R3 is 68K and R4 is 56K, B1 is 1.5 V, B2 is 3.0 V and the current source is equal to the last digit of your student ID Here R is the last digit of your roll no 47 kN 39 kN R Amphere 3.0 V 1.5 V 68 kN 56 kN
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