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For the channel section shown below, calculate the discharge correspond- ing to the flow depth, y = 0.8 +0.6 1.4 ft. Slope, S = 500. Compare your results using the Pavlovskii and Yen equivalent roughness formulae. = 3 ft n₁ = 0.020 Ao (1) 0.6 ft anche y -2 ft- n₂ = 0.015 (2) 3 ft n3 = 0.030 (3) 0.8 ft

For the channel section shown below, calculate the discharge correspond- ing to the flow depth, y = 0.8 +0.6 1.4 ft. Slope, S = 500. Compare your results using the Pavlovskii and Yen equivalent roughness formulae. = 3 ft n₁ = 0.020 Ao (1) 0.6 ft anche y -2 ft- n₂ = 0.015 (2) 3 ft n3 = 0.030 (3) 0.8 ft

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The Pavlovskii and Yen equivalent roughness equations (ne) are attached (second and last equations), please ignore the other formulas besides those two.
Investigator Horton (1933); Einstein (1934) Pavlovskii (1931) Muhlhofer (1933) Einstein and Banks (1950) Lotter (1932) Felkel (1960) Krishnamurthy and Christensen (1972) Yen (1991) - Σ - ΣΦΡ PRS/3 = na PRS/3 n Σ : exp| Ph/2 Inn, ΣPh 3/2 Σ(n.P) P
Transcribed Image Text:Investigator Horton (1933); Einstein (1934) Pavlovskii (1931) Muhlhofer (1933) Einstein and Banks (1950) Lotter (1932) Felkel (1960) Krishnamurthy and Christensen (1972) Yen (1991) - Σ - ΣΦΡ PRS/3 = na PRS/3 n Σ : exp| Ph/2 Inn, ΣPh 3/2 Σ(n.P) P
For the channel section shown below, calculate the discharge correspond- ing to the flow depth, y = 0.8 +0.6 1.4 ft. Slope, S = 500. Compare your results using the Pavlovskii and Yen equivalent roughness formulae. 3 ft n₁ = 0.020 Am 0. (1) 0.6 ft y -2 ft- n₂ = 0.015 (2) = V 3 ft n3 = 0.030 (3) Who Woodlad Nad سلسل الاسم ال 0.8 ft
Transcribed Image Text:For the channel section shown below, calculate the discharge correspond- ing to the flow depth, y = 0.8 +0.6 1.4 ft. Slope, S = 500. Compare your results using the Pavlovskii and Yen equivalent roughness formulae. 3 ft n₁ = 0.020 Am 0. (1) 0.6 ft y -2 ft- n₂ = 0.015 (2) = V 3 ft n3 = 0.030 (3) Who Woodlad Nad سلسل الاسم ال 0.8 ft
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