For the channel section shown below, calculate the discharge correspond- ing to the flow depth, y = 0.8 +0.6 1.4 ft. Slope, S = 500. Compare your results using the Pavlovskii and Yen equivalent roughness formulae. = 3 ft n₁ = 0.020 Ao (1) 0.6 ft anche y -2 ft- n₂ = 0.015 (2) 3 ft n3 = 0.030 (3) 0.8 ft

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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The Pavlovskii and Yen equivalent roughness equations (ne) are attached (second and last equations), please ignore the other formulas besides those two.
Investigator
Horton (1933); Einstein
(1934)
Pavlovskii (1931)
Muhlhofer (1933)
Einstein and Banks (1950)
Lotter (1932)
Felkel (1960)
Krishnamurthy and
Christensen (1972)
Yen (1991)
- Σ
- ΣΦΡ
PRS/3
=
na
PRS/3
n
Σ
: exp|
Ph/2 Inn,
ΣPh
3/2
Σ(n.P)
P
Transcribed Image Text:Investigator Horton (1933); Einstein (1934) Pavlovskii (1931) Muhlhofer (1933) Einstein and Banks (1950) Lotter (1932) Felkel (1960) Krishnamurthy and Christensen (1972) Yen (1991) - Σ - ΣΦΡ PRS/3 = na PRS/3 n Σ : exp| Ph/2 Inn, ΣPh 3/2 Σ(n.P) P
For the channel section shown below, calculate the discharge correspond-
ing to the flow depth, y = 0.8 +0.6 1.4 ft. Slope, S = 500. Compare
your results using the Pavlovskii and Yen equivalent roughness formulae.
3 ft
n₁ = 0.020
Am 0.
(1)
0.6 ft
y
-2 ft-
n₂ =
0.015
(2)
=
V
3 ft
n3 = 0.030
(3)
Who Woodlad Nad
سلسل الاسم ال
0.8 ft
Transcribed Image Text:For the channel section shown below, calculate the discharge correspond- ing to the flow depth, y = 0.8 +0.6 1.4 ft. Slope, S = 500. Compare your results using the Pavlovskii and Yen equivalent roughness formulae. 3 ft n₁ = 0.020 Am 0. (1) 0.6 ft y -2 ft- n₂ = 0.015 (2) = V 3 ft n3 = 0.030 (3) Who Woodlad Nad سلسل الاسم ال 0.8 ft
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