For the cars in the figure below car B is braking and, therefore, accelerating at (-40 km/h2)i relative to point O in the ground reference frame. If car A travels at a constant speed of 20 km/h, what is the acceleration of car B relative to car A reference frame at the time shown in the figure. A 100 m 20 km/h 65 km/h (-68.3 km/h?)i + (-28.3 km/h2)j (40 km/h?)i + (28.3 km/h?)j (28.3 km/h?)i + (28.3 km/h3)j (-40 km/h3ji - (28.3 km/h3]j O 0 o O

For the cars in the figure below car B is braking and, therefore, accelerating at (-40 km/h2)i relative to point O in the ground reference frame. If car A travels at a constant speed of 20 km/h, what is the acceleration of car B relative to car A reference frame at the time shown in the figure. A 100 m 20 km/h 65 km/h (-68.3 km/h?)i + (-28.3 km/h2)j (40 km/h?)i + (28.3 km/h?)j (28.3 km/h?)i + (28.3 km/h3)j (-40 km/h3ji - (28.3 km/h3]j O 0 o O

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter6: Motion In Two Dimensions

Section: Chapter Questions

Problem 84A

See similar textbooks

Similar questions

. You are running north at 4.56ms. Another jogger is jogging north at 2.64ms. From your frame of reference, what is the speed and direction of the other jogger? speed of the other jogger in your frame of reference = ms*Round to the nearest hundredth if necessary. Don’t forget that north is in the positive direction and south is in the negative direction.
A seagull flies at a velocity of 8.5 m/s relative to the air straight into the wind. vSA = 8.5 m/st = 23 mind = 5.8 km A) If it takes the bird 23 min to travel 5.8 km relative to the Earth, what is the velocity of the wind, in meters per second, relative to the Earth? Take the direction of travel of the seagull to be positive. B) If the bird turns around and flies with the wind, how long, in minutes, will it take to return 5.8 km?
Please help me
A seagull flies at a velocity of 9.5 m/s relative to the air straight into the wind. vSA = 9.5 m/st = 24 mind = 5.6 km a)If it takes the bird 24 min to travel 5.6 km relative to the Earth, what is the velocity of the wind, in meters per second, relative to the Earth? Take the direction of travel of the seagull to be positive. b) If the bird turns around and flies with the wind, how long, in minutes, will it take to return 5.6 km?
Please!!! check both papers it is a b and c
The Moon is about 3.8 x 10° m from Earth. Traveling at the speed of light, 3.0 x 10° m/s, how long does it take a laser beam to go from Earth to the Moon and back again (in s)? The same physics was responsible for the noticeable delay in communications signals between lunar astronauts and controllers at the Houston Space Flight Center. S
Solve for the unknown/s. 3. Two particles leave the same point at the same time and both are moving along a horizontal line according to the law s=47³-21² +3 and s=-7+28-10r², respectively. When are they moving at the same speed? Find their positions, velocity and acceleration at that time? 3
You are a construction worker standing still on 12th Ave N in Fargo, and you watch a minivan drive past at 25 mi/hr eastward. A kid in the back throws a ball at his brother in the front seat at 19 mi/hr. How fast does the ball move, as observed by you? (Positive indicates east, negative indicates west.) ? How fast does the ball move, according to the kid who threw it? If instead the kid in the front seat throws a rock at the kid in the back seat at 19 mi/hr, how fast would you observe the rock to travel?
Two boats leave the shore at the same time and travel in the directions shown in (Figure 1). vA = 12 m/s and vB = 19 m/s . A) Determine the magnitude of the velocity of boat A with respect to boat B . B) Determine the direction angle of the velocity of boat A with respect to boat B, measured counterclockwise from the positive x axis. C) How long after leaving the shore will the boats be 480 m apart?
A seagull flies at a velocity of 12.5 m/s relative to the air straight into the wind. vSA = 12.5 m/st = 16 mind = 5.8 km 1. If it takes the bird 16 min to travel 5.8 km relative to the Earth, what is the velocity of the wind, in meters per second, relative to the Earth? Take the direction of travel of the seagull to be positive. 2. If the bird turns around and flies with the wind, how long, in minutes, will it take to return 5.8 km?
Question is in picture attached. Answer is also mentioned in picture containing the question. Kindly check the answer before submitting the solution.
pls send me answer of this question with explanation and i will give you like sure sir.