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For the below circuit and Vs = 125 V, use superposition to find the node voltages VA, VB and Vc: VB R4 R5 1k 1k R8 1k VA R1 Vc R2 1k 2k 20vdc V1 1 R3 3k 0.015Ado 0,

For the below circuit and Vs = 125 V, use superposition to find the node voltages VA, VB and Vc: VB R4 R5 1k 1k R8 1k VA R1 Vc R2 1k 2k 20vdc V1 1 R3 3k 0.015Ado 0,

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Circuit Analysis Using Superposition** **Objective:** For the circuit provided, where \( V_S = 125 \, \text{V} \), apply the principle of superposition to find the node voltages \( V_A \), \( V_B \), and \( V_C \). **Components and Layout:** 1. **Voltage Source:** - \( V_1 = 20 \, \text{VDC} \) 2. **Current Source:** - \( I_1 = 0.015 \, \text{A} \) 3. **Resistors:** - \( R_1 = 2 \, \text{k}\Omega \) - \( R_2 = 1 \, \text{k}\Omega \) - \( R_3 = 3 \, \text{k}\Omega \) - \( R_4 = 1 \, \text{k}\Omega \) - \( R_5 = 1 \, \text{k}\Omega \) - \( R_6 = 1 \, \text{k}\Omega \) - \( R_8 = 1 \, \text{k}\Omega \) **Circuit Description:** - The circuit has a voltage source \( V_1 = 20 \, \text{VDC} \) connected between the ground node and one terminal of \( R_1 \). - Node \( V_A \) connects \( R_1 \), \( R_3 \), \( R_8 \), and \( R_2 \). - Node \( V_B \) connects \( R_4 \), \( R_5 \), and \( R_8 \). - Node \( V_C \) connects \( R_2 \), \( R_5 \), and the current source \( I_1 = 0.015 \, \text{A} \). **Analysis Steps with Superposition:** 1. **Deactivate all sources except one and calculate the contribution to each node voltage.** - For the voltage source \( V_1 \), replace the current source with an open circuit. - For the current source \( I_1 \), replace the voltage source with a short circuit. 2. **Repeat steps for each source, then sum their contributions for \( V_A \), \( V_B \), and \( V_C \).** By following these
Transcribed Image Text:**Circuit Analysis Using Superposition** **Objective:** For the circuit provided, where \( V_S = 125 \, \text{V} \), apply the principle of superposition to find the node voltages \( V_A \), \( V_B \), and \( V_C \). **Components and Layout:** 1. **Voltage Source:** - \( V_1 = 20 \, \text{VDC} \) 2. **Current Source:** - \( I_1 = 0.015 \, \text{A} \) 3. **Resistors:** - \( R_1 = 2 \, \text{k}\Omega \) - \( R_2 = 1 \, \text{k}\Omega \) - \( R_3 = 3 \, \text{k}\Omega \) - \( R_4 = 1 \, \text{k}\Omega \) - \( R_5 = 1 \, \text{k}\Omega \) - \( R_6 = 1 \, \text{k}\Omega \) - \( R_8 = 1 \, \text{k}\Omega \) **Circuit Description:** - The circuit has a voltage source \( V_1 = 20 \, \text{VDC} \) connected between the ground node and one terminal of \( R_1 \). - Node \( V_A \) connects \( R_1 \), \( R_3 \), \( R_8 \), and \( R_2 \). - Node \( V_B \) connects \( R_4 \), \( R_5 \), and \( R_8 \). - Node \( V_C \) connects \( R_2 \), \( R_5 \), and the current source \( I_1 = 0.015 \, \text{A} \). **Analysis Steps with Superposition:** 1. **Deactivate all sources except one and calculate the contribution to each node voltage.** - For the voltage source \( V_1 \), replace the current source with an open circuit. - For the current source \( I_1 \), replace the voltage source with a short circuit. 2. **Repeat steps for each source, then sum their contributions for \( V_A \), \( V_B \), and \( V_C \).** By following these
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