For the beam with the given dimensions, determine the moment capacity using (a) Flexure Theory (b) ACI Equations As' = 15 cm² As = 50 cm² d = 40 cm b = 25 cm d' = 6.5 cm = fc' = 20.7 MPa fs 124.50 MPa Flexure Theory Gross Section ACI Equations 10 nA Transformed Section NA d-x/3 Stress & Internal Couple Diagrams kd/3 kd NA Groen Section Transformed Section Stress & Internal Couple Diagrams

H.W2: For the truss shown below find the horizontal and vertical displacement of joint C. if member AC was made of 1 cm long and placed in its position. 4m D A 90 3m B

Problem 1 An angle bracket ABC is restrained by a high strength steel wire CD, and it supports a load P at A, as shown in figure. The strength properties of the wire and the shear pin at B are , = 350 MPa (wire), and t-300 MPa (pin at B). If the wire and pin are to be sized to provide a factor of safety of the wire F.S = 3.3 and a factor of safety of the pin F.S = 3.5. What are the required diameters of the wire (to the nearest mm) and the pin (to the nearest mm)? D 90 mm 20° 100 mm View a-a of B P = 2 kN

The truss is loaded as shown. 144 kN B 3 m 4 m 4 m 44 kN Analyze it using the method of joints to find all member forces and reactions in kilonewtons. (Assume that the +x-axis is to the right and the +y-axis is up along the page. АВ magnitude kN sense |The magnitude is zero. V AE magnitude kN sense compression ВС magnitude kN sense compression BD magnitude kN sense tension BE magnitude kN sense compression FCD magnitude kN sense The magnitude is zero. V F, DE magnitude kN sense The magnitude is zero. ♥ magnitude kN direction E, magnitude kN direction E, magnitude kN direction