For the aqueous solution of 1500 ppm of NaNO3 (85 g/mol). The Molarity of the solution is 0.0176 M. * For the aqueous solution of 1500 ppm ofNANO3 (85 g/mol). The Molarity of thesolution is 0.0176 M. *TrueO False

Answered: For the aqueous solution of 1500 ppm of…

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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For the aqueous solution of 1500 ppm of NaNO3 (85 g/mol). The Molarity of the solution is 0.0176 M. *

Expert Solution

Step 1

ppm stands for parts per million and

$1 p p m = \frac{1 m g o f s o l u t e}{1 L o f s o l u t i o n}$

and

$1 p p m = \frac{0.001 g o f s o l u t e}{1 L o f s o l u t i o n} (1 g = 0.001 m g)$

Step 2

According to the question:

$c o n c e n t r a t i o n = 1500 p p m = 1500 p p m \times \frac{0.001 \frac{g}{L}}{1 p p m} = 1.500 \frac{g}{L}$

Converting g/L into mol/L

$C o n c e n t r a t i o n (\frac{g}{m o l}) = \frac{C o n c e n t r a t i o n (\frac{g}{L})}{m o l a r m a s s (\frac{g}{m o l})}$

molar mass of NaNO₃ = 85 g/mol

Therefore,

$C o n c e n t r a t i o n (M) = \frac{1.500 \frac{g}{L}}{85 \frac{g}{m o l}} = 0.0176 \frac{m o l}{L} = 0.0176 M$

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For the aqueous solution of 1500 ppm of NANO3 (85 g/mol). The Molarity of the solution is 0.0176 M. * True O False