For the analysis of trace metals it is necessary to prepare solutions of very low concentrations from a stock solution of higher concentration using a micropipette and a volumetric flask. What volume of a 0.0015 M solution of MgCl2(aq) would be required to prepare a 73 nM solution of Mg2+ in a 150 mL flask? O 1.5 HL O 7.3 HL O 15 HL 0.53 HL

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**Preparation of Dilute Solutions from Stock Solutions**

For the analysis of trace metals, it is necessary to prepare solutions of very low concentrations from a stock solution of higher concentration using a micropipette and a volumetric flask. 

**Problem Statement:**
What volume of a 0.0015 M solution of MgCl₂(aq) would be required to prepare a 73 nM solution of Mg²⁺ in a 150 mL flask?

**Options:**
- 1.5 µL
- 7.3 µL
- 15 µL
- 0.53 µL

This exercise involves calculating the correct volume of the more concentrated stock solution needed to achieve the desired lower concentration in a specified volume, using the dilution formula.
Transcribed Image Text:**Preparation of Dilute Solutions from Stock Solutions** For the analysis of trace metals, it is necessary to prepare solutions of very low concentrations from a stock solution of higher concentration using a micropipette and a volumetric flask. **Problem Statement:** What volume of a 0.0015 M solution of MgCl₂(aq) would be required to prepare a 73 nM solution of Mg²⁺ in a 150 mL flask? **Options:** - 1.5 µL - 7.3 µL - 15 µL - 0.53 µL This exercise involves calculating the correct volume of the more concentrated stock solution needed to achieve the desired lower concentration in a specified volume, using the dilution formula.
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