For the analysis of trace metals it is necessary to prepare solutions of very low concentrations from a stock solution of higher concentration using a micropipette and a volumetric flask. What volume of a 0.0015 M solution of MgCl2(aq) would be required to prepare a 73 nM solution of Mg2+ in a 150 mL flask? O 1.5 HL O 7.3 HL O 15 HL 0.53 HL
For the analysis of trace metals it is necessary to prepare solutions of very low concentrations from a stock solution of higher concentration using a micropipette and a volumetric flask. What volume of a 0.0015 M solution of MgCl2(aq) would be required to prepare a 73 nM solution of Mg2+ in a 150 mL flask? O 1.5 HL O 7.3 HL O 15 HL 0.53 HL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Preparation of Dilute Solutions from Stock Solutions**
For the analysis of trace metals, it is necessary to prepare solutions of very low concentrations from a stock solution of higher concentration using a micropipette and a volumetric flask.
**Problem Statement:**
What volume of a 0.0015 M solution of MgCl₂(aq) would be required to prepare a 73 nM solution of Mg²⁺ in a 150 mL flask?
**Options:**
- 1.5 µL
- 7.3 µL
- 15 µL
- 0.53 µL
This exercise involves calculating the correct volume of the more concentrated stock solution needed to achieve the desired lower concentration in a specified volume, using the dilution formula.
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