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For the amplifier shown in Figure 1, the BJT parameters are ß = 75, Vaz (on) = 0.7 V, VCE (sat) = 0.3 V, VA = 100, and V, 25 mv. Voc=9V R = 27 ka 22 ka Rs = 10 ka Ca! E R= C2 kQ R2 = 15 k2 12 kQ The value of the DC base current Ig is

For the amplifier shown in Figure 1, the BJT parameters are ß = 75, Vaz (on) = 0.7 V, VCE (sat) = 0.3 V, VA = 100, and V, 25 mv. Voc=9V R = 27 ka 22 ka Rs = 10 ka Ca! E R= C2 kQ R2 = 15 k2 12 kQ The value of the DC base current Ig is

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For the amplifier shown in Figure 1, the BJT parameters are ß = 75, Vag (on) = 0.7 V, VCE (sat) = 0.3 V, VA = 100, and V, 25 mv. Voe=9V R= 27 ka 22 ka Rs = 10 ka Ca ER= 2 k2 R= 15 k2 12 kQ The value of the DC base current Ig is
Transcribed Image Text:For the amplifier shown in Figure 1, the BJT parameters are ß = 75, Vag (on) = 0.7 V, VCE (sat) = 0.3 V, VA = 100, and V, 25 mv. Voe=9V R= 27 ka 22 ka Rs = 10 ka Ca ER= 2 k2 R= 15 k2 12 kQ The value of the DC base current Ig is
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