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For spring mass system, Mass (m)= 5 kg Time period (T)= 1.2 sec Horizontal displacement =10 mm=0.01 m Assumption: No friction is present Step 2: calculation of frequency and force required a> www time period = f1 T = 27 1.2 = 27 √ 1/2 m k m 2 TT ں) initial position. T= 1.2 Sec = TS ³X 5 10mm 2 TI 23 = 41- 137 0778 N/m • stiffnen of spring k = +

For spring mass system, Mass (m)= 5 kg Time period (T)= 1.2 sec Horizontal displacement =10 mm=0.01 m Assumption: No friction is present Step 2: calculation of frequency and force required a> www time period = f1 T = 27 1.2 = 27 √ 1/2 m k m 2 TT ں) initial position. T= 1.2 Sec = TS ³X 5 10mm 2 TI 23 = 41- 137 0778 N/m • stiffnen of spring k = +

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Find how K is 137.0778 n/m 

For spring mass system, Mass (m) = 5 kg Time period (T)= 1.2 sec Horizontal displacement =10 mm=0.01 m. Assumption: No friction is present Step 2: calculation of frequency and force required a> K www time period f T = 2M m k 1.2= m 2 TT initial positin. T= 1.2 Sec (x) 10 mm YENU 5 F k 211 = 7/1 w3 介 137.0778 N/m stiffnen of spring K =
Transcribed Image Text:For spring mass system, Mass (m) = 5 kg Time period (T)= 1.2 sec Horizontal displacement =10 mm=0.01 m. Assumption: No friction is present Step 2: calculation of frequency and force required a> K www time period f T = 2M m k 1.2= m 2 TT initial positin. T= 1.2 Sec (x) 10 mm YENU 5 F k 211 = 7/1 w3 介 137.0778 N/m stiffnen of spring K =
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