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For R1=58, R2-162, R3=243 and 13-5.5 A in the shown circuit, use KCL and KVL to find the following: R2 13( 1)vo R1 R3 i1 (in Ampere) = 2 a. 5.5 O b. 4.8110151187905 O .0.6889848812095 2 d. 2.4055075593952 i2 (in Ampere) = Oa.-0.6889848812095 Ob.0.6889848812095 Oc.6.1889848812095 2 d. 3.0944924406048

For R1=58, R2-162, R3=243 and 13-5.5 A in the shown circuit, use KCL and KVL to find the following: R2 13( 1)vo R1 R3 i1 (in Ampere) = 2 a. 5.5 O b. 4.8110151187905 O .0.6889848812095 2 d. 2.4055075593952 i2 (in Ampere) = Oa.-0.6889848812095 Ob.0.6889848812095 Oc.6.1889848812095 2 d. 3.0944924406048

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For R1=58, R2=162, R3=243 and 13=5.5 A in the shown circuit, use KCL and KVL to find the following: R2 13( 1)vo R1 ŽR3 i1 (in Ampere) = p a. 5.5 O b. 4.8110151187905 O .0.6889848812095 5 d. 2.4055075593952 i2 (in Ampere) = Oa. -0.6889848812095 O b.0.6889848812095 O c. 6.1889848812095 O d. 3.0944924406048
Transcribed Image Text:For R1=58, R2=162, R3=243 and 13=5.5 A in the shown circuit, use KCL and KVL to find the following: R2 13( 1)vo R1 ŽR3 i1 (in Ampere) = p a. 5.5 O b. 4.8110151187905 O .0.6889848812095 5 d. 2.4055075593952 i2 (in Ampere) = Oa. -0.6889848812095 O b.0.6889848812095 O c. 6.1889848812095 O d. 3.0944924406048
13) SR3 Vo R1 i1 (in Ampere) = O a. 5.5 O b. 4.8110151187905 O C. -0.6889848812095 O d. 2.4055075593952 i2 (in Ampere) = O a. -0.6889848812095 O b. 0.6889848812095 O c. 6.1889848812095 O d. 3.0944924406048 Vo (in volts) = Power of current source (in watt) =
Transcribed Image Text:13) SR3 Vo R1 i1 (in Ampere) = O a. 5.5 O b. 4.8110151187905 O C. -0.6889848812095 O d. 2.4055075593952 i2 (in Ampere) = O a. -0.6889848812095 O b. 0.6889848812095 O c. 6.1889848812095 O d. 3.0944924406048 Vo (in volts) = Power of current source (in watt) =
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