For R1=201, R2=109, R3=328, R4=360, R5=440, R6=210, V1=6 V & 11=3 A in the shown circuit, using the superposition principle find the following: R6 I1 R2 + vi V. FR4 3RI + Io1 (in ampere) due to V1 only= (Note that Io=Iol+Io2, where Iol is due to V1 and Io2 is due to I1) Vol (in volt) due to V1 only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io=Iol+Io2, where Iol is due to V1 and Io2 is due to I1) Vo2 (in volt) due to Il only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1)
For R1=201, R2=109, R3=328, R4=360, R5=440, R6=210, V1=6 V & 11=3 A in the shown circuit, using the superposition principle find the following: R6 I1 R2 + vi V. FR4 3RI + Io1 (in ampere) due to V1 only= (Note that Io=Iol+Io2, where Iol is due to V1 and Io2 is due to I1) Vol (in volt) due to V1 only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io=Iol+Io2, where Iol is due to V1 and Io2 is due to I1) Vo2 (in volt) due to Il only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:For R1=201, R2=109, R3=328, R4=360, R5=440, R6=210, V1=6 V & 11=3 A in the shown circuit, using the superposition principle find the
following:
i,
R6
Il
R2
Vi
Vo R4
ER3
+
Iol (in ampere) due to V1 only=
(Note that Io=Iol+Io2, where Iol is due to V1 and Io2 is due to I1)
Vol (in volt) due to V1 only=
(Note that Vo=Vo1+Vo2, where Vol is due to V1 and Vo2 is due to I1)
Io2 (in ampere) due to Il only=
(Note that Io=Iol+Io2, where Iol is due to V1 and Io2 is due to I1)
Vo2 (in volt) due to Il only=
(Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1)
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