For R1=165, R2=464, R3=374, R4=365, R5=215, R6=215, V1=3 V& 11=4 A in the shown circuit, using the superposition principle find the following: R6 R2 vi R4 R3 RI Iol (in ampere) due to V1 only= (Note that Io=Io1-Io2, where Iol is due to V1 and Io2 is due to I1) Vo1 (in volt) due to V1 only= (Note that Vo=Vo1+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io=Io1-Io2, where Iol is due to V1 and Io2 is due to IIl) Vo2 (in volt) due to Il only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1)
For R1=165, R2=464, R3=374, R4=365, R5=215, R6=215, V1=3 V& 11=4 A in the shown circuit, using the superposition principle find the following: R6 R2 vi R4 R3 RI Iol (in ampere) due to V1 only= (Note that Io=Io1-Io2, where Iol is due to V1 and Io2 is due to I1) Vo1 (in volt) due to V1 only= (Note that Vo=Vo1+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io=Io1-Io2, where Iol is due to V1 and Io2 is due to IIl) Vo2 (in volt) due to Il only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:For R1=165, R2=464, R3=374, R4=365, R5-215, R6=215, V1=3 V & 11=4 A in the shown circuit, using the superposition principle find the following:
R6
R2
vi
V. {R4
R3
ŽRI
Iol (in ampere) due to V1 only=
(Note that Io=lo1÷Io2, where Iol is due to V1 and Io2 is due to I1)
Vo1 (in volt) due to V1 only=
(Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1)
Io2 (in ampere) due to Il only=
(Note that Io-lo1+Io2, where Iol is due to V1 and Io2 is due to I1)
Vo2 (in volt) due to Il only=
(Note that Vo=Vo1+Vo2, where Vol is due to V1 and Vo2 is due to I1)
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