For Questions 11-16: Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question. Given the result from the previous step: {Cr20,2(aq) + 14H* (aq) +6e → 2Cr*3(aq) + 7 H2O (1) } x 1 {HNO2(aq) + H20 (1) + NO3 (aq) + 3H (aq) + 2e} x 3 - Step 6: Recombine the two half reactions and SIMPLIFY the final equation below and report the sum of the coefficients. 18

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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For Questions 11-16:
Balance the following oxidation-reduction reaction in acidic conditions using the half reaction
method by following the step described in each question.
Given the result from the previous step:
{Cr2072(aq) + 14H* (aq) +6e 2Cr*°(aq) + 7 H20 (1) } × 1
{HNO2(aq) + H20 (1) + NO3 (aq) + 3H* (aq) + 2e }x 3
Step 6: Recombine the two half reactions and SIMPLIFY the final equation below and report the
sum of the coefficients.
18
Transcribed Image Text:For Questions 11-16: Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question. Given the result from the previous step: {Cr2072(aq) + 14H* (aq) +6e 2Cr*°(aq) + 7 H20 (1) } × 1 {HNO2(aq) + H20 (1) + NO3 (aq) + 3H* (aq) + 2e }x 3 Step 6: Recombine the two half reactions and SIMPLIFY the final equation below and report the sum of the coefficients. 18
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