For Question 9, Upload your work proving that ... : = -kt + [A] is the Zero-Order Integrated Rate Law by integrating d[A]/dt = -k. ■ [A]t ◉ In[A]t = -kt + In[A]0 is the First-Order Integrated Rate Law by integrating d[A]/dt = -k[A]. Use one of the following strategies: 1. Separate the variables to integrate [A] on the LHS and -k on the RHS. 2. Exponentiate the given rate law above and input the RHS for [A] + on the RHS of your integral, ―k [A]dt.
For Question 9, Upload your work proving that ... : = -kt + [A] is the Zero-Order Integrated Rate Law by integrating d[A]/dt = -k. ■ [A]t ◉ In[A]t = -kt + In[A]0 is the First-Order Integrated Rate Law by integrating d[A]/dt = -k[A]. Use one of the following strategies: 1. Separate the variables to integrate [A] on the LHS and -k on the RHS. 2. Exponentiate the given rate law above and input the RHS for [A] + on the RHS of your integral, ―k [A]dt.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![For Question 9, Upload your work proving that ...
: = -kt + [A] is the Zero-Order Integrated Rate Law by integrating d[A]/dt = -k.
■ [A]t
◉
In[A]t
=
-kt + In[A]0 is the First-Order Integrated Rate Law by integrating d[A]/dt = -k[A]. Use one
of the following strategies:
1. Separate the variables to integrate [A] on the LHS and -k on the RHS.
2. Exponentiate the given rate law above and input the RHS for [A] + on the RHS of your integral,
―k [A]dt.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc45dfd55-2702-405b-9288-88cd78d06c07%2F98155570-cdd2-4c13-a9a0-4addda05ce49%2F6wdlex_processed.png&w=3840&q=75)
Transcribed Image Text:For Question 9, Upload your work proving that ...
: = -kt + [A] is the Zero-Order Integrated Rate Law by integrating d[A]/dt = -k.
■ [A]t
◉
In[A]t
=
-kt + In[A]0 is the First-Order Integrated Rate Law by integrating d[A]/dt = -k[A]. Use one
of the following strategies:
1. Separate the variables to integrate [A] on the LHS and -k on the RHS.
2. Exponentiate the given rate law above and input the RHS for [A] + on the RHS of your integral,
―k [A]dt.
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