For programming C: void chang_pointer(char* bytes_array) { bytes_array = bytes_array + 2; } int main() { bytes_array[1000] = "Hello!\nthis is Man speaking\nHow are u\n"; change_pointer(bytes_array); printf("%s\n",bytes_array); } My question: I have called the "change_pointer()" function to update the char pointer "bytes_array", however the value of it hasnt changed in the main function. Why is this happening? How can i modify a pointer within a function?
For programming C: void chang_pointer(char* bytes_array) { bytes_array = bytes_array + 2; } int main() { bytes_array[1000] = "Hello!\nthis is Man speaking\nHow are u\n"; change_pointer(bytes_array); printf("%s\n",bytes_array); } My question: I have called the "change_pointer()" function to update the char pointer "bytes_array", however the value of it hasnt changed in the main function. Why is this happening? How can i modify a pointer within a function?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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For
void chang_pointer(char* bytes_array) {
bytes_array = bytes_array + 2;
}
int main() {
bytes_array[1000] = "Hello!\nthis is Man speaking\nHow are u\n";
change_pointer(bytes_array);
printf("%s\n",bytes_array);
}
My question:
I have called the "change_pointer()" function to update the char pointer "bytes_array", however the value of it hasnt changed in the main function. Why is this happening? How can i modify a pointer within a function?
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