For problems 1 to 4, use Desmos and state whether the pair of lines are parallel, perpendicular or neither. y = y = 2x + 5 2) 4х — 2у + 6 — 0 2 y = 1) x + y = 4 3) 1 y = 4) =*- 4 y = x – 3 х — 2у + 1 %3D 0
For problems 1 to 4, use Desmos and state whether the pair of lines are parallel, perpendicular or neither. y = y = 2x + 5 2) 4х — 2у + 6 — 0 2 y = 1) x + y = 4 3) 1 y = 4) =*- 4 y = x – 3 х — 2у + 1 %3D 0
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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These are confusing. I sort of get number one, but the other three are confusing.
![For problems 1 to 4, use Desmos and state whether the pair of lines are parallel,
perpendicular or neither.
y = 2x + 5
2)
4х — 2у + 6 %3D0
y =
- 2
y =
1)
x + y = 4
3)
y = x – 3
y = ;x - 4
4)
х — 2у + 1 %3D0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b55393d-e417-4236-b5c9-a151a789ddb2%2F4507daeb-7159-4679-8320-53fb37a0026b%2Fh4mazf9_processed.png&w=3840&q=75)
Transcribed Image Text:For problems 1 to 4, use Desmos and state whether the pair of lines are parallel,
perpendicular or neither.
y = 2x + 5
2)
4х — 2у + 6 %3D0
y =
- 2
y =
1)
x + y = 4
3)
y = x – 3
y = ;x - 4
4)
х — 2у + 1 %3D0
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