For problems # 1 - 5 show the Laplace Transform for the given function is what the chapter states (1) Use integration by parts and the definition of the Laplace transform to justify why L{y'} = s£{y} − y(0) for s> 0 whenever y(t) is bounded. 2 (2) Show that L[r²e²](s) = (s-²1)³ · (3) Show that L[cos(t)](s) = $²+1 (4) Show that L[u(v − 2)](s) = e−²³. (5) Show that L[u(x - 3)x](s) -38 e +3se-3s 82 Solution Solution Solution Solution Solution
For problems # 1 - 5 show the Laplace Transform for the given function is what the chapter states (1) Use integration by parts and the definition of the Laplace transform to justify why L{y'} = s£{y} − y(0) for s> 0 whenever y(t) is bounded. 2 (2) Show that L[r²e²](s) = (s-²1)³ · (3) Show that L[cos(t)](s) = $²+1 (4) Show that L[u(v − 2)](s) = e−²³. (5) Show that L[u(x - 3)x](s) -38 e +3se-3s 82 Solution Solution Solution Solution Solution
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![For problems # 1 - 5 show the Laplace Transform for the given function is what the
chapter states
(1) Use integration by parts and the definition of the Laplace transform to justify
why
L{y'} = s£{y} − y(0) for s> 0 whenever y(t) is bounded.
2
(2) Show that L[x²e²](s) = (s-1)³ ·
(3) Show that L[cos(t)](s) = ²+1
(4) Show that L[u(v − 2)](s) = e−²³.
(5) Show that L[u(x − 3)x](s)
-38
e
+3se-3s
82
Solution
Solution
Solution
Solution
Solution](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fee563bfe-badf-4a9d-9a7e-d47066dc4e0e%2F0351ba61-6cc3-41d0-9efb-382ecc248683%2Frth3h7b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For problems # 1 - 5 show the Laplace Transform for the given function is what the
chapter states
(1) Use integration by parts and the definition of the Laplace transform to justify
why
L{y'} = s£{y} − y(0) for s> 0 whenever y(t) is bounded.
2
(2) Show that L[x²e²](s) = (s-1)³ ·
(3) Show that L[cos(t)](s) = ²+1
(4) Show that L[u(v − 2)](s) = e−²³.
(5) Show that L[u(x − 3)x](s)
-38
e
+3se-3s
82
Solution
Solution
Solution
Solution
Solution
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