For particle size distribution curve for a soil sample D60 is to be 0.42 and D30 is to be 0.045 and D10 is to be 0.005 (For these values find Cu, Cc below) Particle Size Distribution Curve 100 90 70 60 50 20 10 100 10 0.1 0.01 0.001 Particle Size D, mm Cu is equals to: Cc is equals to: Is the soil sample given in the figure above (values are indicated in the figure) Well graded: insert 1 0.0016 0.045 mm +0.224 mm Percent Finer, S, %

For particle size distribution curve for a soil sample D60 is to be 0.42 and D30 is to be 0.045 and D10 is to be 0.005 (For these values find Cu, Cc below) Particle Size Distribution Curve 100 90 70 60 50 20 10 100 10 0.1 0.01 0.001 Particle Size D, mm Cu is equals to: Cc is equals to: Is the soil sample given in the figure above (values are indicated in the figure) Well graded: insert 1 0.0016 0.045 mm +0.224 mm Percent Finer, S, %

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 89 20 0.850 71 40 0.425 47 60 0.250 21 100 0.150 14 200 0.075 7 Pan --- 0 Determine the value of the coefficient of uniformity. Round off to three decimal places.
Problem A: For questions 1 to 7. In the given results of the sieve analysis of a soil. Calculate the following; U.S. Opening Mass Sieve (mm) Retained, grams 4 4.75 10 2.00 21.6 20 0.850 49.50 40 0.425 102.60 60 0.250 89.10 100 0.150 95.60 200 0.075 60.4 Pan 31.2 Sum 1) For the problem above the most probable value for D10=. a) 0.15 mm 2) For D30 =_ a) 0.17 mm 3) For Dso = ? a) 0.27 mm 4) The Uniformity coefficient will be ? a) 4.56 5) The Coefficient of Gradation is? a) 0.90 6) The particle size distribution curve is what type? a) Gap-graded 7) Using the AASHTO system what is the percentage of sand? a) 6.90 b) 0.25 mm c) 0.67 mm d) 0.09 mm b) 0.27 mm c) 0.185 mm d) 0.03 mm b) 0.41mm c) 1.05 mm d) 0.21 mm b) 4.78 c) 3.98 d) 4.21 b) 0.93 c) 0.96 d) 1.15 b) Poorly Graded c) Well-graded b) 4.88 c) 72.90 d) 88.30
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 88 20 0.850 70 40 0.425 50 60 0.250 21 100 0.150 13 200 0.075 5 Pan --- 0 Determine the value of the coefficient of uniformity. Round off to three decimal places.
Show me the diagram also ,.soil
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A sieve analysis is performed for a soil sample. The data are tabulated as shown. Solve Cu
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 96 10 2.000 81 20 0.850 72 40 0.425 50 60 0.250 27 100 0.150 14 200 0.075 5 Pan --- 0 Determine the value of the coefficient of gradation/curvature.
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Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 83 20 0.850 69 40 0.425 50 60 0.250 27 100 0.150 13 200 0.075 7 Pan --- 0 Determine the value of the coefficient of uniformity. ROUND OFF TO THREE DECIMAL PLACES. USE STORED VALUES.
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 97 10 2.000 82 20 0.850 71 40 0.425 42 60 0.250 27 100 0.150 13 200 0.075 8 Pan --- 0 Determine the value of the coefficient of gradation/curvature. Round off to three decimal places.