For part c: Since I already found the MLE for theta in part b, wouldn't the MLE for median be just (theta from part b) divided by square root of 2 (theorem of Invariance of MLE) = max (xi) / 2^1/2 ?
For part c: Since I already found the MLE for theta in part b, wouldn't the MLE for median be just (theta from part b) divided by square root of 2 (theorem of Invariance of MLE) = max (xi) / 2^1/2 ?
For part c: Since I already found the MLE for theta in part b, wouldn't the MLE for median be just (theta from part b) divided by square root of 2 (theorem of Invariance of MLE) = max (xi) / 2^1/2 ?
For part c: Since I already found the MLE for theta in part b, wouldn't the MLE for median be just (theta from part b) divided by square root of 2 (theorem of Invariance of MLE) = max (xi) / 2^1/2 ?
Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.
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