for one trial is p = 0.15. Find the mean for this binomial distribution. (Round answer to one decimal place.) H = 147.5 Find the standard deviation for this distribution. (Round answer to two decimal places.) 11.20 Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value p+20. Enter answer as an interval using square-brackets only with whole numbers. usual values -[ 125,170]
for one trial is p = 0.15. Find the mean for this binomial distribution. (Round answer to one decimal place.) H = 147.5 Find the standard deviation for this distribution. (Round answer to two decimal places.) 11.20 Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value p+20. Enter answer as an interval using square-brackets only with whole numbers. usual values -[ 125,170]
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 16HP
Related questions
Question
![Assume that a procedure yields a binomial distribution with n = 983 trials and the probability of success
for one trial is p = 0.15.
Find the mean for this binomial distribution.
(Round answer to one decimal place.)
147.5
Find the standard deviation for this distribution.
(Round answer to two decimal places.)
11.20
Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value u+20.
Enter answer as an interval using square-brackets only with whole numbers.
usual values = [125,170]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5c3ba4c-cb5e-4df8-996d-5b3ff55de2bb%2Fad0e7e5b-c263-41e4-aa7d-dfbbff00b982%2Flabrsti_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Assume that a procedure yields a binomial distribution with n = 983 trials and the probability of success
for one trial is p = 0.15.
Find the mean for this binomial distribution.
(Round answer to one decimal place.)
147.5
Find the standard deviation for this distribution.
(Round answer to two decimal places.)
11.20
Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value u+20.
Enter answer as an interval using square-brackets only with whole numbers.
usual values = [125,170]
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