For nos. 4 - 7: Consider a saturated solution of barium iodate in 0.025 M BaCl2. Ba(1O3)2(s) = Ba2* + 2103 Ksp = 1.57 x 10-9 at 25°C For the salt: %3D
For nos. 4 - 7: Consider a saturated solution of barium iodate in 0.025 M BaCl2. Ba(1O3)2(s) = Ba2* + 2103 Ksp = 1.57 x 10-9 at 25°C For the salt: %3D
Chapter10: Effect Of Electrolytes On Chemical Equilibria
Section: Chapter Questions
Problem 10.8QAP
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![7. What is pBa in terms of activity of Ba2+?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1aa898f-261b-4d72-9101-d0e9f65d3ef0%2Feebc450b-7e68-47b7-b41b-5ed1d8eea118%2F6xtkrc4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7. What is pBa in terms of activity of Ba2+?
![For nos. 4 - 7: Consider a saturated solution of barium iodate in 0.025 M BaCl2.
For the salt:
Ba(1O3)2(s)
Ba2+ + 2103
Ksp = 1.57 x 10-9 at 25°C
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1aa898f-261b-4d72-9101-d0e9f65d3ef0%2Feebc450b-7e68-47b7-b41b-5ed1d8eea118%2Fidnswjb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For nos. 4 - 7: Consider a saturated solution of barium iodate in 0.025 M BaCl2.
For the salt:
Ba(1O3)2(s)
Ba2+ + 2103
Ksp = 1.57 x 10-9 at 25°C
%3D
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