For Nickel the number density is 8x1023 atoms / cm' and electronic configuration is ls 2s²2p°3s²3p°3d* 4s? . The value of the saturation magnetization of Nickel in its 6 ferromagnetic state is x10° A/m . (Given the value of Bohr magneton µ = 9.21x10" Am? )
For Nickel the number density is 8x1023 atoms / cm' and electronic configuration is ls 2s²2p°3s²3p°3d* 4s? . The value of the saturation magnetization of Nickel in its 6 ferromagnetic state is x10° A/m . (Given the value of Bohr magneton µ = 9.21x10" Am? )
Related questions
Question
![For Nickel the number density is 8×10 atoms / cm' and electronic configuration is
1s 2s 2p°3s²3p°3d* 4s² . The value of the saturation magnetization of Nickel in its
6 -
ferromagnetic state is
x10° A/ m.
(Given the value of Bohr magneton µ, = 9.21x10" Am? )](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6bb44fb-cb74-4b62-8019-da668114b53c%2Fe54e90e3-67c9-4bea-945c-94322bb8ff17%2F4x9w5uc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For Nickel the number density is 8×10 atoms / cm' and electronic configuration is
1s 2s 2p°3s²3p°3d* 4s² . The value of the saturation magnetization of Nickel in its
6 -
ferromagnetic state is
x10° A/ m.
(Given the value of Bohr magneton µ, = 9.21x10" Am? )
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)