For Nickel the number density is 8x1023 atoms / cm' and electronic configuration is ls 2s²2p°3s²3p°3d* 4s? . The value of the saturation magnetization of Nickel in its 6 ferromagnetic state is x10° A/m . (Given the value of Bohr magneton µ = 9.21x10" Am? )
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- (a)A solid metal sphere emits 1.42 ✕ 1020 photons every second with a radiating power of 2.53 W. (a) Determine the energy associated with each photon.Calculate the Landé factors gj of the base states of the following atoms: nickel (3d³4s²), molybdenum (4d55s) and gadolinium (4ƒ75d6s²). Make a diagram of the behavior of the energy levels as a function of the external magnetic field for small fields.As per Bohr model of a hydrogen atom for a stable orbit centripetal, Coulomb, and all forces should be in equilibrium. Therefore, for an electron with mass me and speed v₁ on the nth orbit with radius rn, (k being Coulomb/s constant) mevn = ke²/rn mevn² = ke²/rn mevn²/rn = ke²/rn 2.2 Ome²v² = ke²/r²
- (a)A solid metal sphere emits 1.42 ✕ 1020 photons every second with a radiating power of 2.53 W. (a)Determine the energy associated with each photon. eVThe energy of an electron in the p-level of an atom is changed in the presence of a magnetic field of magnitude 4.6 T. What is the difference between the largest and smallest possible energies as a factor of 10-23 J? (Bohr magneton = μB = 9.27 × 10-24 J/T)[E]216 At an instant, the wave function for an electron is w= f (r,0)e" %12 · Determine the average value of z-component of magnetic moment for the electron. (а) - И в (b) 23 (c) HB (d) 3Дз
- Electrons enter a magnetic field traveling at v, = vỹ. The constant, uniform magnetic field B = 0.75 2 T acts as a filter curving the electrons to a small gap that only allows specific electron energies. The source of electrons enters the filter as a beam that is 15 micrometers in diameter and have a range of energies from 5-25 meV. The filter redirects the beam, as pictured, to the right v = và but does not speed them up. If the filter is to further narrow the range of energies from 5-25 meV to 10-12 meV, find the dimensions of the gap. In the picture, calculate ymin and ymer, both of which can be assumed to be equal to the radius of the paths taken within the magnetic field. %3D The beam being focused to 15 um at the start can be assumed to be a point source and take circular paths within the magnetic field. Outgoing "Filtered" Electrons Blocked Electrons -不: Y Vma Incoming ElectronsThe energy of a photon emitted in a transition from the n = 3 state to the n = 2 state is Question 17 options: 1.5 eV 1.9 eV 3.4 eV 10.2 eV 13.6 eVThe main equation we are using to measure the e/m ratio is: (e/m)=((2v)/(r2B2)) If the anode voltage V is increased by 4 times and the magnetic field was kept constant, the electron beam's deflection radius will be doubled. If we plot V as the y-axis and r2 as the x-axis the slope is equal to: A) (e/m)B2=slope B)(e/m)=slope C)(e/m) (B2/2)=slope