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For methyl chloride at 120°C the second and third virial coefficients are: B = -242.5 cm 3.mol -1 C = 25,200 cm 6.mol -2Calculate the work of mechanically reversible, isothermal compression of 1 mol ofmethyl chloride from 1 bar to 60bar at 120°C. Base calculations on the following forms of the virial equation: (a)Z=1+BV+CV2 (b)Z=1+B'P+C'P2 where B' = B/RTand C'=(C-B2)/(RT)2 (c) Why don't both equations give the same result?

For methyl chloride at 120°C the second and third virial coefficients are: B = -242.5 cm 3.mol -1 C = 25,200 cm 6.mol -2Calculate the work of mechanically reversible, isothermal compression of 1 mol ofmethyl chloride from 1 bar to 60bar at 120°C. Base calculations on the following forms of the virial equation: (a)Z=1+BV+CV2 (b)Z=1+B'P+C'P2 where B' = B/RTand C'=(C-B2)/(RT)2 (c) Why don't both equations give the same result?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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For methyl chloride at 120°C the second and third virial coefficients are: B = -242.5 cm 3.mol -1 C = 25,200 cm 6.mol -2Calculate the work of mechanically reversible, isothermal compression of 1 mol ofmethyl chloride from 1 bar to 60bar at 120°C. Base calculations on the following forms of the virial equation: (a)Z=1+BV+CV2 (b)Z=1+B'P+C'P2 where B' = B/RTand C'=(C-B2)/(RT)2 (c) Why don't both equations give the same result?
Transcribed Image Text:For methyl chloride at 120°C the second and third virial coefficients are: B = -242.5 cm 3.mol -1 C = 25,200 cm 6.mol -2Calculate the work of mechanically reversible, isothermal compression of 1 mol ofmethyl chloride from 1 bar to 60bar at 120°C. Base calculations on the following forms of the virial equation: (a)Z=1+BV+CV2 (b)Z=1+B'P+C'P2 where B' = B/RTand C'=(C-B2)/(RT)2 (c) Why don't both equations give the same result?
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