For many weak acid or weak base calculations, you can use a simplifying assumption to avoid solving quadratic equations. x? x2 Ка [HA] — х [НA] Classify these situations by whether the assumption is valid or the quadratic formula is required. Assumption is valid Quadratic formula is required Answer Bank [HA] = 0.01 M [HA] = 0.1 M [HA] = 0.001 M [HA] = 0.01 M [HA] = 1 M Ka = 1 × 10-5 Ka = 1 × 10-3 Ka = 1 × 10-5 Ka = 1 × 10–4 Ka = 1 × 10-3

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Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.138E: A base is a substance that dissociates in water into one or more ______ ions and one or more...
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For many weak acid or weak base calculations, you can use a simplifying assumption to avoid solving quadratic equations.
x2
x2
Ka
[HA]
[HA]
Classify these situations by whether the assumption is valid or the quadratic formula is required.
Assumption is valid
Quadratic formula is required
Answer Bank
[HA] = 0.01 M
[HA] = 0.1 M
[HA] = 0.001 M
[HA] = 0.01 M
[HA] = 1 M
%3D
Ka = 1 × 10–5
Ka = 1 × 10-3
Ka = 1 x 10-5
Ka = 1 × 10¬4
Ka = 1 × 10-3
%3D
Transcribed Image Text:For many weak acid or weak base calculations, you can use a simplifying assumption to avoid solving quadratic equations. x2 x2 Ka [HA] [HA] Classify these situations by whether the assumption is valid or the quadratic formula is required. Assumption is valid Quadratic formula is required Answer Bank [HA] = 0.01 M [HA] = 0.1 M [HA] = 0.001 M [HA] = 0.01 M [HA] = 1 M %3D Ka = 1 × 10–5 Ka = 1 × 10-3 Ka = 1 x 10-5 Ka = 1 × 10¬4 Ka = 1 × 10-3 %3D
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