For large-k sin(h) 20k = 2 cos(h) – (9.302) 4h k3 and this gives for (Ao, A1, A2) the values sin(h) Ao = cos(h), A1 = 0, A2 (9.303) 8h Substitution of these values into equations (9.292), (9.293), (9.294), and (9.295) gives 0 = 0, Bo = ih, B1 (9.304a) 8h 1 sin(h) 16h sin(h) cos(h) + 8h B2 = (9.304b)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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and that the corresponding asymptotic form for
Yk
is
B1
+
k
B2
k2
Вз
+0
k3
Yk = k°eBok
(9.283)
whoro +he noromotona (0 R.
R.) mor ba oomnlov vol,und and ora
to
These equations may be solved, in turn, to give (Bo, 0, B1, B2). Doing this
gives
Bo = (+) cosh(Ao) = In ( Ao + V A3 – 1
(9.292)
%3D
A1
(9.293)
sinh(Bo)'
[0(0 – 1)
+
sinh(Bo)
A2
B1 =
tanh(Bo),
(9.294)
2
496
Difference Equations
[(1 – 0) cosh(Bo) + 0(0 – 1)/2 – A2]B1
2 sinh(Bo)
0(е — 1)(ө — 2)
B2 =
Аз
(9.295)
2 sinh(Bo)
12
Transcribed Image Text:and that the corresponding asymptotic form for Yk is B1 + k B2 k2 Вз +0 k3 Yk = k°eBok (9.283) whoro +he noromotona (0 R. R.) mor ba oomnlov vol,und and ora to These equations may be solved, in turn, to give (Bo, 0, B1, B2). Doing this gives Bo = (+) cosh(Ao) = In ( Ao + V A3 – 1 (9.292) %3D A1 (9.293) sinh(Bo)' [0(0 – 1) + sinh(Bo) A2 B1 = tanh(Bo), (9.294) 2 496 Difference Equations [(1 – 0) cosh(Bo) + 0(0 – 1)/2 – A2]B1 2 sinh(Bo) 0(е — 1)(ө — 2) B2 = Аз (9.295) 2 sinh(Bo) 12
9.6.3
An Example
To illustrate the use of the technique given in the previous section, consider
the STDE
y"(») + 1+v(e) = 0,
(9.297)
472
(see equation (9.263)). For this case,
1
f(x) = 1+
4x2
(9.298)
and its discretization is
1
fk = f(xk) = f(hk) = 1+
(9.299)
4h?k2 °
Using the Mickens-Ramadhani finite difference discretization, we obtain
1/27
1
Yk+1+ Yk-1 = 2 cos (hVfk)| Yk = 2{ cos h (1+
4h?k2
Yk,
(9.300)
and this gives for
the expression
Ok
1/27
1
= cos |h | 1+
(9.301)
Ok = cos
4h2k2
ADVANCED APPLICATIONS
497
For large-k
20%-2c0()-의 ()+0().
sin(h)
(9.302)
4h
and this gives for (Ao, A1, A2) the values
sin(h)
Ao = cos(h), A1 = 0, A2 = -
8h
(9.303)
Substitution of these values into equations (9.292), (9.293), (9.294), and
(9.295) gives
Co =0,
Bo = ih, Bị = -
8h
(9.304a)
sin(h)
cos(h) +
1
B2
(9.304b)
16h sin(h)
8h
where i = V-1.
If these values are now placed in the yk of equation (9.283) and appropriate
linear combinations of yk and (Yk)* are made, then the following expression
is obtained for the asymptotic solution
cos(Tk)
9 sin(2k)]
2(8k)2
(MR)
A sin(xk)
- a(h) ·
%3D
8xk
9 cos(Tk)]
a(h) ·
2(8®k)?
sin(2k)
+B cos(xk) +
8xk
'(주)아기
+0
(9.305)
where
8h
sin(h)
9 sin(h).
cos(h)
8h
(9.306)
Note that
Ca(0) = Lim a(h):
(9.307)
= 1.
h-0
Also, we have replaced (hk) by Xk.
A similar kind of calculation can be done for the other three finite difference
schemes given in Section 9.6.1, and the results for the asymptotic solutions
are as follows:
cos(o*k)]
8xk
(S)
(Standard scheme) y
= A sin(ørk) – ß.
sin(øæk)]
+ B cos(pxk)+B.
8xk
o(4).
(9.308)
Transcribed Image Text:9.6.3 An Example To illustrate the use of the technique given in the previous section, consider the STDE y"(») + 1+v(e) = 0, (9.297) 472 (see equation (9.263)). For this case, 1 f(x) = 1+ 4x2 (9.298) and its discretization is 1 fk = f(xk) = f(hk) = 1+ (9.299) 4h?k2 ° Using the Mickens-Ramadhani finite difference discretization, we obtain 1/27 1 Yk+1+ Yk-1 = 2 cos (hVfk)| Yk = 2{ cos h (1+ 4h?k2 Yk, (9.300) and this gives for the expression Ok 1/27 1 = cos |h | 1+ (9.301) Ok = cos 4h2k2 ADVANCED APPLICATIONS 497 For large-k 20%-2c0()-의 ()+0(). sin(h) (9.302) 4h and this gives for (Ao, A1, A2) the values sin(h) Ao = cos(h), A1 = 0, A2 = - 8h (9.303) Substitution of these values into equations (9.292), (9.293), (9.294), and (9.295) gives Co =0, Bo = ih, Bị = - 8h (9.304a) sin(h) cos(h) + 1 B2 (9.304b) 16h sin(h) 8h where i = V-1. If these values are now placed in the yk of equation (9.283) and appropriate linear combinations of yk and (Yk)* are made, then the following expression is obtained for the asymptotic solution cos(Tk) 9 sin(2k)] 2(8k)2 (MR) A sin(xk) - a(h) · %3D 8xk 9 cos(Tk)] a(h) · 2(8®k)? sin(2k) +B cos(xk) + 8xk '(주)아기 +0 (9.305) where 8h sin(h) 9 sin(h). cos(h) 8h (9.306) Note that Ca(0) = Lim a(h): (9.307) = 1. h-0 Also, we have replaced (hk) by Xk. A similar kind of calculation can be done for the other three finite difference schemes given in Section 9.6.1, and the results for the asymptotic solutions are as follows: cos(o*k)] 8xk (S) (Standard scheme) y = A sin(ørk) – ß. sin(øæk)] + B cos(pxk)+B. 8xk o(4). (9.308)
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