for (j = n - 1; j> 0; j = j - 1) Factorial ( n ) { if n=1 for (i = 0; i A[ i+ 1]) return n * Factorial ( n - 1) Temp= A[ i ]; A[ i] = A[ i+ 1]; A[ i+1] = Temp; RecMinimum (A[], I, r) if r-ls1 return min (A[ 1], A[ r ])) else mid = [(ltr)/2] ml = RecMinimum (A, I, mid)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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e) Find the time complexity of the codes shown below:
Factorial ( n )
for (j = n - 1; j> 0; j = j - 1)
{
{
if n= 1
for (i = 0; i<j; i=i+1)
{
if (A[ i]> A[ i+ 1])
{
return 1
else
return n * Factorial ( n - 1)
}
Temp= A[ i ];
RecMinimum (A[], 1, r)
if r-1<1
return min (A[ 1], A[ r ]))
else
A[ i] = A[ i+1];
A[ i+ 1] = Temp;
mid = [(ltr)/2]
ml = RecMinimum (A, I, mid)
m2 = RecMinimum (A, mid+1, r)
return (min(m1,m2))
}
}
Activ
Transcribed Image Text:e) Find the time complexity of the codes shown below: Factorial ( n ) for (j = n - 1; j> 0; j = j - 1) { { if n= 1 for (i = 0; i<j; i=i+1) { if (A[ i]> A[ i+ 1]) { return 1 else return n * Factorial ( n - 1) } Temp= A[ i ]; RecMinimum (A[], 1, r) if r-1<1 return min (A[ 1], A[ r ])) else A[ i] = A[ i+1]; A[ i+ 1] = Temp; mid = [(ltr)/2] ml = RecMinimum (A, I, mid) m2 = RecMinimum (A, mid+1, r) return (min(m1,m2)) } } Activ
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