For items 3-4, use the following vectors: a A=z²i-yzj-k 3. Vector Calculus-Solve V-(A x C) a 2yz-2xy + zy²2³ b. -2r³yz-2r-y³2² - 2yz c. 2z²y²-2zz + 3z²z² + 2y²z d. -3zz +2y²²-2z+zyz³ e. None of the choices 4. Vector Calculus - Solve V x D y cos² (y) cos(y) C=-zi-z²j+zy²zk cos² +5²) ₁ + (1 - 000²(1) ) * -2 cos(y)√²+y (₁zcos² (y)) B = cos(2z)i + sin(yz)j D=21+rcos² (y)k; r = √√√² + y²

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I have these 2 mcqs. Need correct answer with explanation Handwriting please solve Asap. These 2 questions dont say it multiple questions it's subparts like. Need 3 and 4 mcqs solve for me with explanation.
C.
y cos² (y)
x² + y²
d.
cos²
-2 cos(y) sin(y) √² + y² +2.
2² +3²) 1+ (2- TOS²(y)) ₁
+
y cos² (y)
√x² + y²
e. None of the choices
x cos²
√/2² + x²) ₁+ (2_ Joos (W) ) ₁ + (2_+sin()) k
(x² + y²
y²
- cos(y) sin(y)√x² + y² + 2
Transcribed Image Text:C. y cos² (y) x² + y² d. cos² -2 cos(y) sin(y) √² + y² +2. 2² +3²) 1+ (2- TOS²(y)) ₁ + y cos² (y) √x² + y² e. None of the choices x cos² √/2² + x²) ₁+ (2_ Joos (W) ) ₁ + (2_+sin()) k (x² + y² y² - cos(y) sin(y)√x² + y² + 2
For items 3-4, use the following vectors:
3. Vector Calculus - Solve V (AXC)
a 2yz - 2xy + xy²₂³
b. -2r³yz-2r-y³²-2yz
a
A = r²i-yzj-k
c. 2z²y² - 2xz + 3x²z² + 2y²z
d. -3x2 + 2y²z²-2z+zyz³
e. None of the choices
4. Vector Calculus - Solve V x D
y cos² (y)
b.
C=-zi-a²j+ry²zk
cos(y)
cos²
+5²) ₁ + (₁ - 200² (01)² ) i
k
+
2 cos(y) √² + y²
-2 cos(y) sin(y)√² + y² + z cos² (y)
+(₂-
2
B = cos(2z)i + sin(yz)j
D = 21+ r cos² (y)k; r = √√√² + y²
Transcribed Image Text:For items 3-4, use the following vectors: 3. Vector Calculus - Solve V (AXC) a 2yz - 2xy + xy²₂³ b. -2r³yz-2r-y³²-2yz a A = r²i-yzj-k c. 2z²y² - 2xz + 3x²z² + 2y²z d. -3x2 + 2y²z²-2z+zyz³ e. None of the choices 4. Vector Calculus - Solve V x D y cos² (y) b. C=-zi-a²j+ry²zk cos(y) cos² +5²) ₁ + (₁ - 200² (01)² ) i k + 2 cos(y) √² + y² -2 cos(y) sin(y)√² + y² + z cos² (y) +(₂- 2 B = cos(2z)i + sin(yz)j D = 21+ r cos² (y)k; r = √√√² + y²
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