For items 21- 24, your answer will be the sum of all the numerical coefficients of the reactants and products (use H' instead of H30") Ex. 2AO + H*- 2 H20 +3B2 Answer 2 +1 + 2+3 =8 21. Cr20,2+ CI => Crt + Cl2 (Acidic) Question 22 22. Cr20,2-+ CI → Cr3* + Cl2 (Basic) 23. CN' + AsO, AsO2 + CNO (Basic)

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For items 21 -24, your answer will be the sum of all the numerical coefficients of the
reactants and products (use H' instead of H3O')
Ex. 2AO + H*-→ 2 H2O +3B2 Answer 2 +1 + 2 +3 =8
21. Cr20,2 + CI => Cr3+ + Cl2 (Acidic)
Question 22
22. Cr20,2- + CI → Cr + Cl2 (Basic)
23. CN+ AsO4 → AsO2 + CNO (Basic)
Question 24
24. H2O2 + KMNO4 + H2SO4 → K2SO4 + MNSO4 + H20 + 02
(Hint: Make the total number of electrons lost and gained equal by writing
appropriate coefficients for both reducing and oxidizing agents. Then, balance the rest of
the equation by inspection)
Transcribed Image Text:For items 21 -24, your answer will be the sum of all the numerical coefficients of the reactants and products (use H' instead of H3O') Ex. 2AO + H*-→ 2 H2O +3B2 Answer 2 +1 + 2 +3 =8 21. Cr20,2 + CI => Cr3+ + Cl2 (Acidic) Question 22 22. Cr20,2- + CI → Cr + Cl2 (Basic) 23. CN+ AsO4 → AsO2 + CNO (Basic) Question 24 24. H2O2 + KMNO4 + H2SO4 → K2SO4 + MNSO4 + H20 + 02 (Hint: Make the total number of electrons lost and gained equal by writing appropriate coefficients for both reducing and oxidizing agents. Then, balance the rest of the equation by inspection)
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