For item 17-18. Let R be the partial ordering on A = {1, 2, 3, 4, 8, 12} defined by xRy if and only if x divides y. 17. The maximal elements are 8 and 12. 18. The least upper bound of the set {2, 4} is 8.

Q: Part 2. Each relation given below is a partial order. Draw the Hasse diagram for the partial order.…

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Q: (c) 60 70 M 30 14 6 10 | | 3 5 7 2 20 바 30 6 3 60 20 10 | 5 70 14 7

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A: solution :          Let  A={3 , 5 , 6 , 7 , 10 , 14 , 20 , 30 , 60}and the relation P is defited by…

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Q: 60 30 20 20 10 10 (iii) (iv) Figure 4: A Hasse diagram shows a set of elements, 3, 5, 6, 7, 10, 14,…

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A: To draw the Hasse diagram for the below partial order. Given that: Domain: 3,5,6,7,10,14,20,30,60…

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A: Hi!. You have posted a question with multiple subparts. As per our policy, we will only solve for…