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For Exercises 23–28, write the answer as a single term and simplify. It is not necessary to rationalize the denominator. 2Vx + 4 2rV16 – * + Vx + 4 V16 – x 23. 24. (Vx + 4) (V16 – x) 25. (х — 4)/3 26. (х + 5)/4 + + 3(x 4)2/3 4(x + 5)3/4 2x -1/2[ (x + 1)(2) – 2x(1) 3x -2/3[ (x + 1) • 3 – 3x(2x) 27. 28. \x + 1. (x + 1)? x² + (x? + 1)?

For Exercises 23–28, write the answer as a single term and simplify. It is not necessary to rationalize the denominator. 2Vx + 4 2rV16 – * + Vx + 4 V16 – x 23. 24. (Vx + 4) (V16 – x) 25. (х — 4)/3 26. (х + 5)/4 + + 3(x 4)2/3 4(x + 5)3/4 2x -1/2[ (x + 1)(2) – 2x(1) 3x -2/3[ (x + 1) • 3 – 3x(2x) 27. 28. \x + 1. (x + 1)? x² + (x? + 1)?

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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For Exercises 23–28, write the answer as a single term and simplify. It is not necessary to rationalize the denominator. 2Vx + 4 2rV16 – * + Vx + 4 V16 – x 23. 24. (Vx + 4) (V16 – x) 25. (х — 4)/3 26. (х + 5)/4 + + 3(x 4)2/3 4(x + 5)3/4 2x -1/2[ (x + 1)(2) – 2x(1) 3x -2/3[ (x + 1) • 3 – 3x(2x) 27. 28. \x + 1. (x + 1)? x² + (x? + 1)?
Transcribed Image Text:For Exercises 23–28, write the answer as a single term and simplify. It is not necessary to rationalize the denominator. 2Vx + 4 2rV16 – * + Vx + 4 V16 – x 23. 24. (Vx + 4) (V16 – x) 25. (х — 4)/3 26. (х + 5)/4 + + 3(x 4)2/3 4(x + 5)3/4 2x -1/2[ (x + 1)(2) – 2x(1) 3x -2/3[ (x + 1) • 3 – 3x(2x) 27. 28. \x + 1. (x + 1)? x² + (x? + 1)?
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