For every positive integer n     12+22+32+...+n2=n(n+1)(2n+1)/6 Let S(n)=12+22+32+...+n2 How do you get the basic and inductive step

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For every positive integer n     12+22+32+...+n2=n(n+1)(2n+1)/6

Let S(n)=12+22+32+...+n2

How do you get the basic and inductive step?

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