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For electric circuit shown in Figure find currents in each resistor. 22 is www 32 -40 6V 4-_-_2

For electric circuit shown in Figure find currents in each resistor. 22 is www 32 -40 6V 4-_-_2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Electric Circuit Analysis** **Problem Statement:** For the electric circuit shown in the figure, find the currents in each resistor. **Circuit Description:** The circuit consists of the following components: 1. A 2V battery connected to a 2Ω resistor. 2. The 2Ω resistor is in series with a 1Ω resistor. 3. The 1Ω resistor connects back to the negative terminal of the 2V battery, forming a loop. 4. From the junction between the 2Ω and 1Ω resistors, a branch goes up connecting to a 3Ω resistor. 5. A 4V battery is connected in parallel with the 3Ω resistor. 6. In addition, there is a 6V battery in series with a 4Ω resistor connected across a second loop. **Circuit Diagram Explanation:** - The circuit consists of two loops. - The left loop contains the 2V battery, the 2Ω resistor, and the 1Ω resistor. - The right loop contains the 4Ω resistor and the 6V battery. - The 3Ω resistor and the 4V battery create another connection between the two loops. **Objective:** Determine the current flowing through each resistor (2Ω, 1Ω, 3Ω, and 4Ω). **Step-by-Step Analysis:** 1. Apply Kirchhoff's Voltage Law (KVL) to each loop to set up the equations. 2. Use Kirchhoff's Current Law (KCL) at junctions if needed. 3. Solve the simultaneous equations to find current values. **Key Steps:** 1. Identify loops and label the currents. 2. Write the KVL equations for each loop. 3. Solve for the currents. By performing these steps, you will be able to find the current through each resistor in the circuit. **Note:** Detailed mathematical calculations and solutions would follow based on the application of Kirchhoff's Laws.
Transcribed Image Text:**Electric Circuit Analysis** **Problem Statement:** For the electric circuit shown in the figure, find the currents in each resistor. **Circuit Description:** The circuit consists of the following components: 1. A 2V battery connected to a 2Ω resistor. 2. The 2Ω resistor is in series with a 1Ω resistor. 3. The 1Ω resistor connects back to the negative terminal of the 2V battery, forming a loop. 4. From the junction between the 2Ω and 1Ω resistors, a branch goes up connecting to a 3Ω resistor. 5. A 4V battery is connected in parallel with the 3Ω resistor. 6. In addition, there is a 6V battery in series with a 4Ω resistor connected across a second loop. **Circuit Diagram Explanation:** - The circuit consists of two loops. - The left loop contains the 2V battery, the 2Ω resistor, and the 1Ω resistor. - The right loop contains the 4Ω resistor and the 6V battery. - The 3Ω resistor and the 4V battery create another connection between the two loops. **Objective:** Determine the current flowing through each resistor (2Ω, 1Ω, 3Ω, and 4Ω). **Step-by-Step Analysis:** 1. Apply Kirchhoff's Voltage Law (KVL) to each loop to set up the equations. 2. Use Kirchhoff's Current Law (KCL) at junctions if needed. 3. Solve the simultaneous equations to find current values. **Key Steps:** 1. Identify loops and label the currents. 2. Write the KVL equations for each loop. 3. Solve for the currents. By performing these steps, you will be able to find the current through each resistor in the circuit. **Note:** Detailed mathematical calculations and solutions would follow based on the application of Kirchhoff's Laws.
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