For each transistor in the circuit in Figure P5.79, ß = 120 and the B–E tun- on voltage is 0.7 V. Determine the quiescent base, collector, and emitter cur- rents in Q, and Q2. Also determine Vergi and VCrga-

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### Transcription of the Circuit Diagram

**Figure P5.79: Bipolar Junction Transistor (BJT) Amplifier Circuit**

---

#### Component Descriptions:

- **Voltage Source (\( v_s \)):**
  - A generic AC voltage source is connected on the left.

- **Resistors:**
  - \( R_1 = 100 \, \text{k}\Omega \): Connected in series with the voltage source \( v_s \).
  - \( R_2 = 40 \, \text{k}\Omega \): Connected in parallel to the combination of \( R_1 \) and \( C_c \).
  - \( R_{C1} = 3 \, \text{k}\Omega \): Collector resistor for transistor \( Q_1 \).
  - \( R_{E1} = 1 \, \text{k}\Omega \): Emitter resistor for transistor \( Q_1 \).
  - \( R_{C2} = 5 \, \text{k}\Omega \): Collector resistor for transistor \( Q_2 \).

- **Transistors:**
  - Two NPN Bipolar Junction Transistors (\( Q_1 \) and \( Q_2 \)) are used.
  - \( Q_1 \) is configured in the Common Emitter configuration.
  - \( Q_2 \) follows \( Q_1 \) in a cascaded design to enhance amplification.

- **Capacitor:**
  - \( C_C \): Coupling capacitor. It is used to block DC while allowing AC signals to pass through.

#### Power Supplies:

- **+10 V**: The positive power supply connected to the collector of \( Q_1 \) and \( Q_2 \) through \( R_{C1} \) and \( R_{C2} \).
- **-10 V**: The negative power supply is connected to the lower terminals.

#### Output Voltage:

- \( v_O \): The output voltage is taken across the collector resistor \( R_{C2} \) of the second transistor \( Q_2 \).

---

### Explanation:

This diagram features a two-stage BJT amplifier circuit. The signal from the voltage source \( v_s \) is amplified through a combination of resistors and transistors. The coupling capacitor \( C_C \) ensures only the AC component of the input signal is carried forward, while the resistors and transistors
Transcribed Image Text:### Transcription of the Circuit Diagram **Figure P5.79: Bipolar Junction Transistor (BJT) Amplifier Circuit** --- #### Component Descriptions: - **Voltage Source (\( v_s \)):** - A generic AC voltage source is connected on the left. - **Resistors:** - \( R_1 = 100 \, \text{k}\Omega \): Connected in series with the voltage source \( v_s \). - \( R_2 = 40 \, \text{k}\Omega \): Connected in parallel to the combination of \( R_1 \) and \( C_c \). - \( R_{C1} = 3 \, \text{k}\Omega \): Collector resistor for transistor \( Q_1 \). - \( R_{E1} = 1 \, \text{k}\Omega \): Emitter resistor for transistor \( Q_1 \). - \( R_{C2} = 5 \, \text{k}\Omega \): Collector resistor for transistor \( Q_2 \). - **Transistors:** - Two NPN Bipolar Junction Transistors (\( Q_1 \) and \( Q_2 \)) are used. - \( Q_1 \) is configured in the Common Emitter configuration. - \( Q_2 \) follows \( Q_1 \) in a cascaded design to enhance amplification. - **Capacitor:** - \( C_C \): Coupling capacitor. It is used to block DC while allowing AC signals to pass through. #### Power Supplies: - **+10 V**: The positive power supply connected to the collector of \( Q_1 \) and \( Q_2 \) through \( R_{C1} \) and \( R_{C2} \). - **-10 V**: The negative power supply is connected to the lower terminals. #### Output Voltage: - \( v_O \): The output voltage is taken across the collector resistor \( R_{C2} \) of the second transistor \( Q_2 \). --- ### Explanation: This diagram features a two-stage BJT amplifier circuit. The signal from the voltage source \( v_s \) is amplified through a combination of resistors and transistors. The coupling capacitor \( C_C \) ensures only the AC component of the input signal is carried forward, while the resistors and transistors
**Transcription for Educational Website**

**Problem 5.79**

For each transistor in the circuit in Figure P5.79, the current gain (\( \beta \)) is 120, and the base-emitter (B–E) turn-on voltage is 0.7 V. Determine the quiescent base, collector, and emitter currents in transistors \( Q_1 \) and \( Q_2 \). Also determine \( V_{CEQ1} \) and \( V_{CEQ2} \). 

*Note: Figure P5.79 is referenced for circuit details but is not provided in this text.*
Transcribed Image Text:**Transcription for Educational Website** **Problem 5.79** For each transistor in the circuit in Figure P5.79, the current gain (\( \beta \)) is 120, and the base-emitter (B–E) turn-on voltage is 0.7 V. Determine the quiescent base, collector, and emitter currents in transistors \( Q_1 \) and \( Q_2 \). Also determine \( V_{CEQ1} \) and \( V_{CEQ2} \). *Note: Figure P5.79 is referenced for circuit details but is not provided in this text.*
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