For each problem, calculate the directional derivative in the given direction and the gradient vector: 11. z = x² - 6y²; P (7,2); a) 0 = 45°; b) 0 = 135° 12. z = ye*; P(0,3); a) 0 = 30°; b) 0 = 120° 13. z = x² + xy + y²; P (3,1); 0 = 14. z = x3 + y3 – 3xy; P(2,1); 0 = arctan (²)
For each problem, calculate the directional derivative in the given direction and the gradient vector: 11. z = x² - 6y²; P (7,2); a) 0 = 45°; b) 0 = 135° 12. z = ye*; P(0,3); a) 0 = 30°; b) 0 = 120° 13. z = x² + xy + y²; P (3,1); 0 = 14. z = x3 + y3 – 3xy; P(2,1); 0 = arctan (²)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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pls solve all
do not provide solution in image format thank you!
![Directional Derivative and Gradient Vector
For each problem, calculate the directional derivative in the given direction and the gradient vector:
11. z = x² - 6y2; P(7,2); a) 0 = 45°; b) 0 = 135°
12. z = ye*; P(0,3); a) 0 = 30°; b) 0 = 120°
13. z = x² + xy + y²; P (3,1); 0 =
14. z = x3 + y3 – 3xy; P(2,1); 0 = arctan
NIM](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F56b4ab23-f6d5-4206-a94e-63cad8267fd4%2F4c3bcfce-3c59-4c90-b873-aea2b466b375%2Fz5j9sqi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Directional Derivative and Gradient Vector
For each problem, calculate the directional derivative in the given direction and the gradient vector:
11. z = x² - 6y2; P(7,2); a) 0 = 45°; b) 0 = 135°
12. z = ye*; P(0,3); a) 0 = 30°; b) 0 = 120°
13. z = x² + xy + y²; P (3,1); 0 =
14. z = x3 + y3 – 3xy; P(2,1); 0 = arctan
NIM
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