For each part below, consider the area enclosed between the curves y = 2+1, from 1 = 0 to x = 3/1/2 -2x and y = a) Sketch the region (Note that one of the intersection points of the two curves is very close to x = 2) b) Set up the integral uses disk or washers to compute the volume of the solid created by rotating the given area the given area about the line y=3 c) Set ир the integral that uses shells to compute the volume of the solid created by rotating the given area about the line = x==2

Q: y² = 4-4x y² =4-x. and the x-axis. and 3. The region is bounded by the curve a) Find the volume of…

A:

Q: a) Sketch the region enclosed by the curves y = -10 + x, y = -x? - 8. b) Find the area of the region…

A: The given functions are y=-10+x2 and y=-x2-8

Q: 15. Sketch the region enclosed by the lines x = 3 and y = 1 and the curve xy = 9, and find its area.

A: The area between curves is the area between a curve fx and a curve gx on an interval a, b given…

Q: 2)Find the area between y2=x and y=X-2 by using: a) Vertical strip. b)Horizontal strip.

A: First we need to identify the region which bounded by these two curves. With the help of the sketch…

Q: I Sketch the area bounded by x² + 2y = 4 and x+y+2=0 and determine: d) area using horizontal strip…

A:

Q: Consider the curves x = 12y? and x + 6y = 18. a) Determine their points of intersection (x1, Y1) and…

A: Given :   x=12y2 x+6y=18

Q: b) Find the area of the region enclosed between the curves y = x-1 and y= x-3? (Sketch the region)

A:

Q: 1)Find the area bounded by the given curves: a)y = 6x2 and y = 24   b)y = 3x2 − 12 and y = 0

A: The given function are y=6x2 and y=24. The area bounded by the given curves as shown below:

Q: What is the volume of the torus whose region is inside the circle

A: (x-3)2 + y2 = 1. Take it as the form (x-b)2 + y2 = a2, where b=3 and a=1.